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3 years ago

What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.

Mathematics

1 answer:

schepotkina [342]3 years ago

6 0

Answer:

Step-by-step explanation:

The given equation of line is

$3x+6y=-18$

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

$3x+6y+18=0$ ...(i)

If a line is defined as $ax+bx+c=0$ , then the slope of the line is

$m=-\dfrac{a}{b}$

In equation (i), a=3, b=6 and c=18. So, slope of the line is

$m_1=-\dfrac{3}{6}=-\dfrac{1}{2}$

Let $m_2$ be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

$m_1\cdot m_2=-1$

$(-\dfrac{1}{2})\cdot m_2=-1$

Multiply both sides by -2.

$m_2=2$

Therefore, the slope of perpendicular line is 2.

You might be interested in

The length, 18 meters, is the answer to the following question.

VLD [36.1K]

Answer:

L = B + 3 ..................(1)

L × B = 270 m² .................(2)

on solving we get

L = 18 m, B = 15 m

Step-by-step explanation:

Let the length of the rectangle be L

and,

Width of the rectangle be 'B'

thus,

according to the question

L = B + 3 ..................(1)

And, area of the rectangle = 270 m²

also,

Area of the rectangle = L × B = 270 m² ...........(2)

on substituting 'L' from equation 1 in equation 2, we get

( B + 3 ) × B = 270

B² + 3B - 270 = 0

B² + 18B - 15B - 270 = 0

B( B + 18 ) - 15(B + 18) = 0

( B - 15 ) × ( B + 18 ) = 0

thus, we get

B = 15 m (accepted ) and B = -18 m (neglected : since the length cannot be negative)

therefore,

From 1, we get

L = 15 + 3 = 18 m

8 0

4 years ago

6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1

jeka57 [31]

Answer:

111111 $\times$ 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}$

First of all, let us solve the first term:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111$

Now, the right term:

$\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111$