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1 year ago

Max points!! help please!!! tyyyyy

Mathematics

2 answers:

Viefleur [7K]1 year ago

8 0

Answer:

Its B.70

Step-by-step explanation:

It would be 70 cause the other ones would't match with the amount of cars or people.

I hope it helps you!

krek1111 [17]1 year ago

6 0

Answer:

b. 70

Step-by-step explanation:

The Binomial Coefficient can be used to calculate the number of ways objects can be arranged.

Binomial Coefficient

$\displaystyle \rm \binom{n}{r} \: = \:^{n}C_{r} = \frac{n!}{r!(n-r)!}$

The exclamation mark "!" placed after a number means factorial and indicates to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

The Binomial Coefficient gives us the number of ways of picking "r" unordered outcomes from "n" possibilities.

As there are 8 friends ⇒ n = 8.

As each car takes 4 friends ⇒ r = 4.

Substitute these values into the formula:

$\begin{aligned} \implies \displaystyle \rm \binom{8}{4} \: = \:^{8}C_{4} & = \rm \frac{8!}{4!(8-4)!}\\\\ & = \rm \dfrac{8 \times 7\times 6\times 5\times 4\times 3\times 2\times 1}{4\times 3\times 2\times 1\times 4\times 3\times 2\times 1}\\\\ & = \rm \dfrac{8 \times 7\times 6\times 5}{4\times 3\times 2\times 1}\\\\ & = \rm \dfrac{1680}{24}\\\\ & = \rm 70\end{aligned}$

Learn more about the binomial coefficient here:

brainly.com/question/27802390

brainly.com/question/27800539

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strojnjashka [21]

Step-by-step explanation:

going around the field one time is walking all 4 sides.

so, 4×13 m

going around the field 5 times is walking all 4 sides 5 times.

that means

5×4×13 m = 20×13 = 260 m

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3 years ago

Consider f(x) = 1.8x – 10 and g(x) = −4.

erastova [34]

Answer:

Step-by-step explanation:

The input value at which f(x) = g(x) can be found by setting the right sides of each of those equal to each other and solving for x.

1.8x - 10 = -4 and

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x = 3 1/3

The bold equation is the answer to the first part, and the second part is that x = 3 1/3

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3 years ago

Read 2 more answers

Large cheese pizzas cost $5 each and large one-topping pizzas cost $6 each.

dsp73

Answer:

$T=5c+6d$

Step-by-step explanation:

The correct question is

Large cheese pizzas cost $5 each and large one-topping pizzas cost $6 each.

Write an equation that represents the total cost, T, of c large cheese pizzas and d large one-topping pizzas.

Let

T -----> the total cost

c ----> the number of large cheese pizzas

d ---> the number of large one -topping pizzas

we know that

The total cost (T) is equal to the number of large cheese pizzas (c) multiplied by it cost ($5) plus the number of large one -topping pizzas (d) multiplied by it cost ($6)

$T=5c+6d$

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3 years ago

2. Write 1.68 as a simplified fraction

Alex787 [66]

 $1 \frac{68}{100 }$

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3 years ago

Find the point P on the graph of the function y=√x closest to the point (9,0)

Sphinxa [80]

Answer:

$\displaystyle \frac{17}{2}$ .

Step-by-step explanation:

Let the $x$ -coordinate of $P$ be $t$ . For $P\!$ to be on the graph of the function $y = \sqrt{x}$ , the $y$ -coordinate of $\! P$ would need to be $\sqrt{t}$ . Therefore, the coordinate of $P \!$ would be $\left(t,\, \sqrt{t}\right)$ .

The Euclidean Distance between $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ is:

$\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}$ .

The goal is to find the a $t$ that minimizes this distance. However, $\sqrt{t^2 - 17 \, t + 81}$ is non-negative for all real $t\!$ . Hence, the $\! t$ that minimizes the square of this expression, $\left(t^2 - 17 \, t + 81\right)$ , would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ .

Differentiate $\left(t^2 - 17 \, t + 81\right)$ with respect to $t$ :

$\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17$ .

$\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2$ .

Set the first derivative, $(2\, t - 17)$ , to $0$ and solve for $t$ :

$2\, t - 17 = 0$ .

$\displaystyle t = \frac{17}{2}$ .

Notice that the second derivative is greater than $0$ for this $t$ . Hence, $\displaystyle t = \frac{17}{2}$ would indeed minimize $\left(t^2 - 17 \, t + 81\right)$ . This $t\!$ value would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ , the distance between $P$ $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ .

Therefore, the point $P$ would be closest to $(9,\, 0)$ when the $x$ -coordinate of $P\!$ is $\displaystyle \frac{17}{2}$ .

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