Question

Find the derivative of g(y)=(y-4)*(2y+y^2)

Answer 1

Answer:

$g'(y)=3y^2-4y-8$

Step-by-step explanation:

start by foiling out the given function

$g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y$

next, use the power rule to find the derivative

power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.

$g'(y)=3y^2-4y-8$