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kirill [66]
1 year ago
7

Find the derivative of g(y)=(y-4)*(2y+y^2)

Mathematics
1 answer:
sasho [114]1 year ago
5 0

Answer:

g'(y)=3y^2-4y-8

Step-by-step explanation:

start by foiling out the given function

g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y

next, use the power rule to find the derivative

power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.

g'(y)=3y^2-4y-8

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JulijaS [17]

Answer:

C) 5

Step-by-step explanation:

5 0
2 years ago
May someone please help me out on this question
NISA [10]

Answer:

A

Step-by-step explanation:

It's hard to see but when x is 6, y is 4.5. Just plug that into each equation and see which one is correct.

x^{2} =8y\\x=6;y=4.5\\6^{2} =8(4.5)\\36=36

8 0
3 years ago
Im stuck on this question, plz help
denis-greek [22]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

40 metres covered in 6 seconds

Max speed attained after 6seconds

75 meters covered after 11 seconds

Average Speed for first 40 meters :

Speed = distance / time

Speed = 40m / 6s

Speed = 6.67m/s

To obtain the maximum speed :

Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds

Speed at this point is maximum :

Hence, maximum speed = (35m / 5s) = 7m/s

Suppose, Manuel runs for an additional z seconds after reaching max speed :

Distance from starting line 6+z seconds after race started?

Distance after 6 seconds = 40 metres

Distance after z seconds = 7 * z

Total distance = (40 + 7z)

What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?

Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))

40 + 7(x - 6)

3 0
3 years ago
Please help me? _XYZ is translated 4 units up and 3 units left to yield _X_Y_Z_. What is the distance between any two correspond
natka813 [3]
<span>Every point went up 4 units and left 3 units.
</span><span>Point X on the triangle moved up 4 and left 3. That formed a right triangle with legs 4 and 3. The distance point X moved to point X', d, is the hypotenuse of the right triangle.
</span><span>Using the Pythagoras Theorem
</span><span><span>3^2</span>+<span>4^2</span>=<span>d^2
d = 5

</span></span>
7 0
3 years ago
Please can you help me with this problems. Thanks.
KengaRu [80]
1. Pants=2, shirts= 3
# outcomes 2*3=6

2. Flavors=3, toppings= 4
# outcomes 3*4= 12

3. Type=3, color=3
# outcomes 3*3= 9
4 0
3 years ago
Read 2 more answers
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