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Nana76 [90]
2 years ago
6

Solve using the substitution method. Show steps please.

Mathematics
1 answer:
rusak2 [61]2 years ago
7 0

Answer:

X=1, Y=4

Step-by-step explanation:

IN THE ATTACHED FILE

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Which of the following formulas would find the lateral area of a right cylinder
zmey [24]

Answer:

2πrh unit^2.

Step-by-step explanation:

The lateral area is  the circumference of the base * the height =  2πrh.

6 0
2 years ago
I need help on this 2 please help​
Dovator [93]

Answer:

If we are working in a coordinate plane where the endpoints has the coordinates (x1,y1) and (x2,y2) then the midpoint coordinates is found by using the following formula:

midpoint=(x1+x22,y1+y22)

Step-by-step explanation:

6 0
2 years ago
Solve the following equations: (a) x^11=13 mod 35 (b) x^5=3 mod 64
tino4ka555 [31]

a.

x^{11}=13\pmod{35}\implies\begin{cases}x^{11}\equiv13\equiv3\pmod5\\x^{11}\equiv13\equiv6\pmod7\end{cases}

By Fermat's little theorem, we have

x^{11}\equiv (x^5)^2x\equiv x^3\equiv3\pmod5

x^{11}\equiv x^7x^4\equiv x^5\equiv6\pmod 7

5 and 7 are both prime, so \varphi(5)=4 and \varphi(7)=6. By Euler's theorem, we get

x^4\equiv1\pmod5\implies x\equiv3^{-1}\equiv2\pmod5

x^6\equiv1\pmod7\impleis x\equiv6^{-1}\equiv6\pmod7

Now we can use the Chinese remainder theorem to solve for x. Start with

x=2\cdot7+5\cdot6

  • Taken mod 5, the second term vanishes and 14\equiv4\pmod5. Multiply by the inverse of 4 mod 5 (4), then by 2.

x=2\cdot7\cdot4\cdot2+5\cdot6

  • Taken mod 7, the first term vanishes and 30\equiv2\pmod7. Multiply by the inverse of 2 mod 7 (4), then by 6.

x=2\cdot7\cdot4\cdot2+5\cdot6\cdot4\cdot6

\implies x\equiv832\pmod{5\cdot7}\implies\boxed{x\equiv27\pmod{35}}

b.

x^5\equiv3\pmod{64}

We have \varphi(64)=32, so by Euler's theorem,

x^{32}\equiv1\pmod{64}

Now, raising both sides of the original congruence to the power of 6 gives

x^{30}\equiv3^6\equiv729\equiv25\pmod{64}

Then multiplying both sides by x^2 gives

x^{32}\equiv25x^2\equiv1\pmod{64}

so that x^2 is the inverse of 25 mod 64. To find this inverse, solve for y in 25y\equiv1\pmod{64}. Using the Euclidean algorithm, we have

64 = 2*25 + 14

25 = 1*14 + 11

14 = 1*11 + 3

11 = 3*3 + 2

3 = 1*2 + 1

=> 1 = 9*64 - 23*25

so that (-23)\cdot25\equiv1\pmod{64}\implies y=25^{-1}\equiv-23\equiv41\pmod{64}.

So we know

25x^2\equiv1\pmod{64}\implies x^2\equiv41\pmod{64}

Squaring both sides of this gives

x^4\equiv1681\equiv17\pmod{64}

and multiplying both sides by x tells us

x^5\equiv17x\equiv3\pmod{64}

Use the Euclidean algorithm to solve for x.

64 = 3*17 + 13

17 = 1*13 + 4

13 = 3*4 + 1

=> 1 = 4*64 - 15*17

so that (-15)\cdot17\equiv1\pmod{64}\implies17^{-1}\equiv-15\equiv49\pmod{64}, and so x\equiv147\pmod{64}\implies\boxed{x\equiv19\pmod{64}}

5 0
3 years ago
Please answer if you think you are kind and beautiful of world
tia_tia [17]

Answer:

y = 0

Step-by-step explanation:

Given (-5, 0) and (0, 0),

Find the slope (m):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 0}{0 - (-5)} = \frac{0}{5} = 0

Slope (m) = 0.

Find the y-intercept (b):

y-intercept (b) = 0. This is the value of y, when x = 0.

To write the equation of the line, substitute m = 0, and b = 0 into y = mx + b

y = (0)(x) + 0

y = 0 + 0

y = 0

6 0
3 years ago
Ricardo has agreed to tutor for the school. He owes his older brother $59 and would like to end the summer with at least $400 in
Dvinal [7]

Answer:

44 or 45

Step-by-step explanation:

400 divided by nine

5 0
2 years ago
Read 2 more answers
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