Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 =
tan 18 =
∴ x = ................ (1)
In ΔOBC
tan 14 =
tan 14 =
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x =
x =
∵ tan 18 + tan 14 = 0.574
<em>∴ x = 113.2 ft</em>
<em>i.e. The her distance from the pole is 113.2 ft.</em>
The equation of the parallel line is y = –2x – 11.
Solution:
Given equation of the line is y = –2x – 5.
Slope of this line is = –2
To write the equation parallel to this line and passes through (–4, –3).
<em>If two lines are parallel, then they have the same slope.</em>
<u>Point-slope formula:</u>
Substitute the given values in the formula, we get
Subtract 3 from both sides of the equation.
Hence the equation of the parallel line is y = –2x – 11.
