The given operation involves just swapping the two rows, so carrying out 
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
Which of the following could be the side lengths of a right triangle
1 answer:
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The mean of n numbers is the sum of the numbers divided by n.
You have a mean score of 84 after taking 5 tests. Let x be the sum of scores.
You scored a total of 420 points on five tests.
You need to have a mean score of 85 after taking 6 tests. Let y be the score you need to obtain. Your total score on 6 tests is 420+y.
You need to score 90 points on the sixth test.
You have a mean score of 84 after taking 5 tests. Let x be the sum of scores.
You scored a total of 420 points on five tests.
You need to have a mean score of 85 after taking 6 tests. Let y be the score you need to obtain. Your total score on 6 tests is 420+y.
You need to score 90 points on the sixth test.
Answer:
The probability is
Step-by-step explanation:
From the question we are told that
The proportion that live with their parents is
The sample size is n = 125
Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution
i.e
Now the mean is evaluated as
Generally the proportion that are not staying with parents is
= >
The standard deviation is mathematically evaluated as
Given the n is large then we can use normal approximation to evaluate the probability as follows
Now applying continuity correction
Generally
So for the z - table