2cos^2 x + 3sin x = 0
2(1 - sin^2 x) + 3sin x = 0
2 - 2sin^2 x + 3sin x = 0
2sin^2 x - 3sin x - 2 = 0
Let sin x = m, then
2m^2 - 3m - 2 = 0
2m^2 + m - 4m - 2 = 0
m(2m + 1) - 2(2m + 1) = 0
(m - 2)(2m + 1) = 0
m = 2 or m = -1/2
Now, sin x = -1/2
Therefore, x = 1/6(12nπ - π) and 1/6(12nπ + 7π)
Answer:
Option 2: m∠1 = 147°, m∠2 = 80°, m∠3 = 148°
Step-by-step explanation:
Step 1: Consider triangle ABC from the picture attached below.
Lets find angle x
x + 47 + 33 = 180 (because all angles of a triangle are equal to 180°)
x = 100°
Angle x = Angle y = 100° (because vertically opposite angles are equal)
Step 2: Find angle 2
Angle 2 = 180 - angle x (because angle on a straight line is 180°)
Angle 2 = 180 - 100
Angle 2 = 80°
Step 3: Find angle z
48 + y + z = 180° (because all angles of a triangle are equal to 180°)
z = 32°
Angle 3 = 180 - angle z (because angle on a straight line is 180°)
Angle 3 = 180 - 32
Angle 3 = 148°
Step 4: Find angle 1
Angle 1 = 180 - 33 (because angle on a straight line is 180°)
Angle 1 = 147°
Therefore m∠1 = 147°, m∠2 = 80°, m∠3 = 148°
Option 2 is correct
!!
Answer:
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Answer: x^2 -10x + 24
Step-by-step explanation:
(x-6) (x-4)
= x^2 - 6x - 4x + 24
= x^2 -10x + 24
see the attached figure to better understand the problem
we know that
1) If angle 1 and angle 2 are complementary angles
then
m∠1+m∠2=
------> equation A
2) If angle 1 and angle 2 are congruent angles
then
m∠1=m∠2 ------> equation B
Substitute equation B in equation A
m∠1+(m∠1)=
2m∠1=
m∠1=
therefore
<u>the answer is</u>