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1 year ago

Give an example of this when adding two rationalnumbers with different signs and provide the product.

Mathematics

1 answer:

kolezko [41]1 year ago

5 0

ANSWER:

$\begin{gathered} \frac{4}{5}+-\frac{8}{3}=-\frac{28}{15} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{32}{15} \end{gathered}$

STEP-BY-STEP EXPLANATION:

Rational numbers are all numbers that can be expressed as a fraction, that is, as the quotient of two whole numbers.

Therefore, an example would be:

$\begin{gathered} \frac{4}{5}\text{ and - }\frac{8}{3} \\ \text{adding} \\ \frac{4}{5}+-\frac{8}{3}=\frac{4}{5}-\frac{8}{3} \\ \frac{4}{5}-\frac{8}{3}=\frac{4\cdot3-5\cdot8}{5\cdot3}=\frac{12-40}{15}=-\frac{28}{15} \\ \text{ product} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{4\cdot8}{5\cdot3}=-\frac{32}{15} \end{gathered}$

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How do you do this TwT

tangare [24]

Answer:

Step-by-step explanation:

First step plug the numbers into the equation.

-10/(5+2) = (-10/5) + (-10/2)

Solve both sides of the equation separately.

-10/(5+2) Use distributive property, multiply both 5 and 2 by -10.

= -50 + (-20) = -70

-10/5 + -10/2 Multiply the fractions so they can be added together.

-10/5*2 = -20/10 -10/2*5 = -50/10

-20/10 + -50/10 = -70

Now you have solved both equations and they are both equal to -70, so you have verified that the equations are equal to each other because they both equal -70.

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2 years ago

Given:

Natali [406]

Answer:

$\overline{PM}\cong\overline{ON}$ :, Segment subtended by the same angle on two adjacent parallel lines are congruent

Step-by-step explanation:

Statement, Reason

MNOP is a parallelogram:, Given

$\overline{PM}\left | \right |\overline{ON}$ :, Opposite sides of a parallelogram

∠PMO ≅ ∠MON:, Alternate Int. ∠s Thm.

$\overline{MN}\left | \right |\overline{PO}$ :, Opposite sides of a parallelogram

∠POM ≅ ∠NMO:, Alternate Int. ∠s Thm.

OM ≅ OM:, Reflexive property

$\overline{PM}\cong\overline{ON}$ :, Segment subtended by the same angle and on two adjacent parallel lines are congruent

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3 years ago

Suppose a certain type of fertilizer has an expected yield per acre of mu 1 with variance sigma 2, whereas the expected yield fo

mart [117]

Answer:

See the proof below.

Step-by-step explanation:

For this case we just need to apply properties of expected value. We know that the estimator is given by:

$S^2_p= \frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2}$

And we want to proof that $E(S^2_p)= \sigma^2$

So we can begin with this:

$E(S^2_p)= E(\frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2})$

And we can distribute the expected value into the temrs like this:

$E(S^2_p)= \frac{(n_1 -1) E(S^2_1) +(n_2 -1) E(S^2_2)}{n_1 +n_2 -2}$

And we know that the expected value for the estimator of the variance s is $\sigma$ , or in other way $E(s) = \sigma$ so if we apply this property here we have:

$E(S^2_p)= \frac{(n_1 -1 )\sigma^2_1 +(n_2 -1) \sigma^2_2}{n_1 +n_2 -2}$

And we know that $\sigma^2_1 = \sigma^2_2 = \sigma^2$ so using this we can take common factor like this:

$E(S^2_p)= \frac{(n_1 -1) +(n_2 -1)}{n_1 +n_2 -2} \sigma^2 =\sigma^2$

And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.

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3 years ago

Please answer this correctly

bazaltina [42]

Answer:

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3 years ago

Draw one card at random from a standard deck of cards. the sample space s is the collection of the 52 cards. assume that the pro

olchik [2.2K]

In probability problems, look out for the word OR and AND.

OR means adding the probability
AND means multiplying the probability

P(a) = P(jack) + P(queen) + P(king) = (4/52) + (4/52) + (4/52) = 12/52 = 3/13

P(b) = [P(9) + P(10) + P(jack)] × P(red) = [(4/52) + (4/52) + (4/52)] × (26/52)
P(b) = (12/52) × (26/52) = 3/26

P(c) = 13/52 = 1/4

P(d) = P(a diamond) + P(a heart) + P(a spade) = (13/52) + (13/52) + (13/52) = 3/4

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3 years ago