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ladessa [460]
1 year ago
10

A chemical equation contains 4 hydrogen atoms and 2 oxygen atoms in the reactants. How many hydrogen and oxygen atoms should be

in the products according to the law of conservation of matter? Responses 2 hydrogen atoms and 4 oxygen atoms 2 hydrogen atoms and 4 oxygen atoms 1 hydrogen atom and 1 oxygen atom 1 hydrogen atom and 1 oxygen atom, 4 hydrogen atoms and 2 oxygen atoms 4 hydrogen atoms and 2 oxygen atoms 5 hydrogen atoms and 1 oxygen atom 5 hydrogen atoms and 1 oxygen atom
Mathematics
1 answer:
Fittoniya [83]1 year ago
5 0

The number of hydrogen and oxygen atoms that should be in the products according to the law of conservation of matter, is given as follows:

4 hydrogen atoms and 2 oxygen atoms.

<h3>What is stated by the law of conservation of matter?</h3>


The law of conservation of matter states that the amount of matter in the solution remains constant, even when the substance has a change in the format.

The amounts on the equation are given as follows:

  • 4 hydrogen atoms.
  • 2 oxygen atoms in the reactants.

The law of conservation of matter states that the amounts remain constant, hence the amounts of the solution are given as follows:

  • 4 hydrogen atoms.
  • 2 oxygen atoms in the reactants.

More can be learned about the law of conservation of matter at brainly.com/question/18318085

#SPJ1

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Answer:

The solutions for the given system of equations are:

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Step-by-step explanation:

Given the equation system:

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We obtain the following matrix:

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<u>Step 1:</u> Multiply the fisrt row by 1/3.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]

<u>Step 2:</u> Sum the first row and the second row.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]

<u>Step 3:</u> Multiply the second row by 3/4.

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<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.

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The result of the reduced matrix is:

\left \{ {{x=-5} \atop {y+4z=12}} \right.

This is equal to:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

These are the solutions for the system of equations in terms of z, where z can be any number.

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