What is nine times a number x, in algebraic expression?

If you got your 60% discount and opened up the card for an additional 20%, what is the actual % discount you would receive?

Alinara [238K]

Answer:

80 I guess.................

6 0

3 years ago

For her cellular service, Vera pays $32 a month, plus $0.75 for each minute over the allowed minutes in her plan. Write an expre

svlad2 [7]

Well, "m" represent $32 she spends a month and "t" be the $0.75 for each minute will be.

First, since the bill is for one month, we can place "m" by itself with no add-ons to it since it's been stated only a month is going by and it stays $32. However, depending of "t" the price can change without the original monthly plan changing, so we write it like m + (t . x). "x" represent every minute spent over the time limit, so it's "t" times "x" since whatever "t" is is determined by "x". If "x" is 0, then "t" is 0 since nothing is added and it'd remain $32. If say "x" was 10 however, that would mean 10 minutes have gone over the limit, so 0.75 x 10 would be $7.50 + $32 making it $39.50.
Your answer is m + (t . x)
Note: "m" and "t" can be different if you choose.

7 0

3 years ago

Please help as fast as you cannn

hodyreva [135]

Answer:

-43 < -35

(Negative 43 is less than negative 35).

8 0

3 years ago

A particular plant root grows 1.5 inches per month. How many centimeters is the plant root growing per month? (1 inch = 2.54 cen

Lady bird [3.3K]

You convert inches into centimeters
2.54*1.5=3.81

The answer to this question is 3.81

4 0

3 years ago

Read 2 more answers

On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar is known to be normally dist

Fofino [41]

Answer:

a) $8469-1.645\frac{100}{\sqrt{64}}=8448.4$

$8469+1.645\frac{100}{\sqrt{64}}=8489.6$

So on this case the 90% confidence interval would be given by (8448.4;8489.6)

b) $8469-2.054\frac{100}{\sqrt{64}}=8443.33$

$8469+2.054\frac{100}{\sqrt{64}}=8494.68$

So on this case the 96% confidence interval would be given by (8443.33;8494.68)

Step-by-step explanation:

Assuming this complete problem: On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar is known to be normally distributed with s = 100. The composition of the bar has been slightly modified, but the modification is not believed to have affected either the normality or the value of s.

(a) Assuming this to be the case, if a sample of 64 modified bars resulted in a sample average yield point of 8469 lb, compute a 90% CI for the true average yield point of the modified bar. (Round your answers to one decimal place.)

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8469$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=100$ represent the population standard deviation

n=64 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.645$

Now we have everything in order to replace into formula (1):

$8469-1.645\frac{100}{\sqrt{64}}=8448.4$

$8469+1.645\frac{100}{\sqrt{64}}=8489.6$

So on this case the 90% confidence interval would be given by (8448.4;8489.6)

(b) How would you modify the interval in part (a) to obtain a confidence level of 96%? (Round your answer to two decimal places.)

Since the Confidence is 0.96 or 96%, the value of $\alpha=0.04$ and $\alpha/2 =0.02$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.02,0,1)".And we see that $z_{\alpha/2}=2.054$

Now we have everything in order to replace into formula (1):

$8469-2.054\frac{100}{\sqrt{64}}=8443.33$

$8469+2.054\frac{100}{\sqrt{64}}=8494.68$

So on this case the 96% confidence interval would be given by (8443.33;8494.68)

7 0

3 years ago

What is nine times a number x, in algebraic expression?​

What is nine times a number x, in algebraic expression?