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lidiya [134]
3 years ago
5

Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each day, she finds 12 more seashells

on the beach. Katie can use fractions of days to find seashells.
Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer: 5 1/2

Step-by-step explanation:

This is nroebsu

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The scale from a garden to this drawing is 8 ft to 1 cm. the scale from the same garden to another drawing is 2 ft to 1 cm. what
garik1379 [7]

The lengths of the base and height of the garden in the other scale drawing are 0.6 cm and 0.9 cm. So, option A is correct.

What is the scale factor?

The scale factor is calculated by                                                                     Scale factor = Length of the new drawing ÷ length of the original drawing

Calculation:

It is given that,

For the given triangle drawing, the scale from a garden to this drawing is 8 ft to 1 cm. The scale from the same garden to another drawing is 2 ft to 1 cm.

So, we can compute the scale factors as

8 ft to 1 cm = 1/8 cm

2 ft to 1 cm = 1/2 cm

Then the scale factor for the required lengths is 1/8 ÷ 1/2 = 1/4 cm

Thus, the required lengths are:

The base of the garden on the other scale drawing is

= 2.4 cm × 1/4

= 0.6 cm

The height of the garden on the other scale drawing is

= 3.6 cm × 1/4

= 0.9 cm

Therefore, the lengths of the base and the garden on the other scale drawing are 0.6 cm and 0.9 cm. So, option A is correct.

The given question in the portal was incomplete. Here is the complete question.

Question: The scale from a garden to this drawing is 8 ft to 1 cm. The scale from the same garden to another drawing is 2 ft to 1 cm. What are the lengths of the base and height of the garden in the other scale drawing?

A) 0.6 cm and 0.9 cm

B) 1.2 cm and 1.8 cm

C) 4.8 cm and 7.2 cm

D) 9.6 cm and 14.4 cm

Learn more about scale factors here brainly.com/question/28307342

#SPJ4

5 0
2 years ago
Write an equation in slope-intercept form for the line.<br><br> Slope -2, passes through (-3,14)
LekaFEV [45]

Answer:

y=-2x +8

Step-by-step explanation:

8 0
3 years ago
How can I solve this? 10+x = 5(1/5x + 2)
pshichka [43]
You use PEMDAS. Start by distributing the terms in the parentheses. The isolate the variables. To do that you subtract x from one side of the equation to the other side. You always do the other operation. If it is adding you subtract, if your multiplying your dividing and the other way around. Then you subtract 10 from each side. This equation has many solution because all the terms cancel out.
5 0
3 years ago
Hey ! I’m trying to find the slope. If you could help me that’ll be great thank you !!
galben [10]

Answer:

The answer is B. 1

Step-by-step explanation:

rise over run

1/1=1

4 0
3 years ago
Read 2 more answers
(10 points)Assume IQs of adults in a certain country are normally distributed with mean 100 and SD 15. Suppose a president, vice
vesna_86 [32]

Answer:

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Step-by-step explanation:

To solve this question, we need to use the binomial and the normal probability distributions.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability the president will have an IQ of at least 107.5

IQs of adults in a certain country are normally distributed with mean 100 and SD 15, which means that \mu = 100, \sigma = 15

This probability is 1 subtracted by the p-value of Z when X = 107.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{107.5 - 100}{15}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 probability that the president will have an IQ of at least 107.5.

Probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

First, we find the probability of a single person having an IQ of at least 130, which is 1 subtracted by the p-value of Z when X = 130. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{130 - 100}{15}

Z = 2

Z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

Now, we find the probability of at least one person, from a set of 2, having an IQ of at least 130, which is found using the binomial distribution, with p = 0.0228 and n = 2, and we want:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.9772)^{2}.(0.0228)^{0} = 0.9549

P(X \geq 1) = 1 - P(X = 0) = 0.0451

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

What is the probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130?

0.3085 probability that the president will have an IQ of at least 107.5.

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Independent events, so we multiply the probabilities.

0.3082*0.0451 = 0.0139

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

8 0
3 years ago
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