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Aleksandr [31]
1 year ago
15

FeSO4(aq) + K3PO4 (aq) —>

Chemistry
1 answer:
ch4aika [34]1 year ago
5 0

An ionic equation is a chemical equation in which the electrolytes in aqueous solution are described as dissociated ions.

<h3>What is the difference between ionic equation and net ionic equation?</h3>
  • A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.
  • A molecular formula has two or more atoms bonded together, whereas a chemical formula can only refer to one atom. They are both elements, and their chemical symbols are unchanged.
  • An ionic equation is a chemical equation in which the electrolytes in aqueous solution are described as dissociated ions. It is similar to a molecular equation in that it expresses compounds as molecules.

3FeSO4(aq) + 2K3PO4(aq) = Fe3(PO4)2(s) + 3K2SO4(aq)

ionic equation : 3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

net ionic equation: 3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)  

K2CO3(aq) + CdI2(aq) = 2KI(aq) + CdCO3(s)

net ionic equation for K2CO3(aq) + CdI2(aq) = 2KI(aq) + CdCO3(s).

2HNO3 + CaCO3 = Ca(NO3)2 + H2O + CO2

ionic equation :  CaCO3(s) + 2H+(aq) → Ca2+(aq) + CO2(g) + H2O()

To learn more about :   Ionic equation

Ref :  brainly.com/question/19705645

#SPJ13

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Given the following values for the change in enthalpy (deltaH) and entropy (deltaS), which of the following processes can occur
Shtirlitz [24]

Answer:

Option A and B

Explanation:

(a) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = Delta H – T * DS

Substituting the given values, we get –  

Delta G = -84 -298 *(125/1000) = -121.25  KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(b) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = -125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G =-84 -298 *(-125/1000) = -46.75 KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(c) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = 84 -298 *(125/1000) = +46.75 KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

(d) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G = 84 -298 *(-125/1000) = + 121.25  KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

6 0
3 years ago
Heisenberg's uncertainty principle tells us that _____. heisenberg's uncertainty principle tells us that _____. the de broglie w
Alexandra [31]

Based on Heisenberg's uncertainty principle, the position and velocity of a particle cannot be determined simultaneously with accuracy.

In other words, Heisenberg's uncertainty principle states that the more accurately we know the position of a particle the less accurately we can know its velocity. Mathematically it is given as:

Δx.mΔv >= h/2π

where: Δx = uncertainty in position

m = mass

Δv = uncertainty in velocity

h = plancks constant

   


3 0
4 years ago
Read 2 more answers
The electronegativity of an atom generally _______ going down columns and _______ going left to right across rows. An element li
blondinia [14]

Answer:

B

Explanation:

The electronegativity of an atom is a chemical property of that atom that describes the tendency of the atom in question to attract a lone pair of electrons towards itself.

Across the periods, that is going from left to right on the periodic table, it is expected that there is an increase in the electronegativity of elements. Hence, there are more electronegative elements on the right hand side of the periodic table. Thus, we say chlorine or fluorine is more electronegative than either sodium and magnesium.

While it is expected to increase across the period, electronegativity decreases down the group. Hence, we know that chlorine is more electronegative than bromine while fluorine is more electronegative than chlorine. In fact, fluorine is the most electronegative element as it is the first member of the most electronegative group of elements.

Fluorine and oxygen are expected to undergo a covalent bond formation. Both are electron deficient and thus completes their electron orbits by entering into covalent bonding with each other

8 0
3 years ago
A runner wants to run 12.8 km . She knows that her running pace is 7.1 mi/h .
Alexus [3.1K]
<span>67.2 minutes
 
First convert the runner's speed from mi/h to km/h by multiplying by 1.60934 km/mi, giving 7.1 mi/h * 1.60934 km/mi = 11.43 km/h Divide the distance by her speed. 12.8 km / (11.43 km/h) = 1.12 h Convert hours to minutes by multiplying by 60 1.12 h * 60 min/h = 67.2 min</span>
5 0
4 years ago
Consider the reaction to produce methanolCO(g) + 2H2 (g) &lt;-----&gt; CH3OHAn equilibrium mixture in a 2.00-L vessel is found t
MariettaO [177]

Answer : The value of K_c of the reaction is 10.5 and the reaction is product favored.

Explanation : Given,

Moles of CH_3OH at equilibrium = 0.0406 mole

Moles of CO at equilibrium = 0.170 mole

Moles of H_2 at equilibrium = 0.302 mole

Volume of solution = 2.00 L

First we have to calculate the concentration of CH_3OH,CO\text{ and }H_2 at equilibrium.

\text{Concentration of }CH_3OH=\frac{\text{Moles of }CH_3OH}{\text{Volume of solution}}=\frac{0.0406mole}{2.00L}=0.0203M

\text{Concentration of }CO=\frac{\text{Moles of }CO}{\text{Volume of solution}}=\frac{0.170mole}{2.00L}=0.085M

\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.302mole}{2.00L}=0.151M

Now we have to calculate the value of equilibrium constant.

The balanced equilibrium reaction is,

CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)

The expression of equilibrium constant K_c for the reaction will be:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the values in this expression, we get :

K_c=\frac{(0.0203)}{(0.085)\times (0.151)^2}

K_c=10.5

Therefore, the value of K_c of the reaction is, 10.5

There are 3 conditions:

When K_{c}>1; the reaction is product favored.

When K_{c}; the reaction is reactant favored.

When K_{c}=1; the reaction is in equilibrium.

As the value of K_{c}>1. So, the reaction is product favored.

7 0
3 years ago
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