n=20 mol
(NH)4 SO4
Atomic masses :
N- 14
H- 1
S- 32
O- 16
Therefore M= 14×2 + 1×8 + 32 + 16×4
= 132
m= nM
= 20×132
= 2640g
Answer:
V/V% = 8.2%
Explanation:
Given data:
Volume of methanol = 37.5 mL
Volume of solution = 456 mL
V/V% = ?
Solution:
V/V% = [volume of solute / volume of solution ]×100
V/V% = 37.5 mL / 456 mL × 100
V/V% = 0.08× 100
V/V% = 8.2%
Answer:
0.362 moles
Explanation:
Mass of butane = 21g
Molar mass of carbon = 12g / mol
Molar mass of hydrogen = 1g/mol
Molar mass of butane ? = [(12*4) * (1*10)]
Molar mass of butane = 58g / mole
Number of moles = mass of molecules / molar mass of molecule
Number of moles = 21 / 58
Number of moles of butane = 0.362 moles
The number of moles in 21g of butane is 0.362 moles