True I’m pretty sure! Hope I helped
Lets understand that biotic factors are living and abiotic factors are non living.
1. I see a fish and plants
2. The water
3. The biotic factor which is the fish interacts with the water which is abiotic by swimming and breathing it in with its gills.
4.The plant which is a biotic factor could be taken out. This would affect the aquarium because the fish would have nothing to feed on.
5. One abiotic factor you could change would be the water. You could take it out and the biotic factors wouldn't survive without it.
Answer:
Explanation:
Adenine an Guanine are purines while cytosine and thymine are pyrimidines.
According to Chargaff's rule, the ratio of purines to pyrimidines is equal.
Thus, the number of cytosine (C) will be equal to the number of guanine (G).
As it is given that the number of guanine-containing nucleotides = 410
Thus, G = C = 410
Now, G + C = 410 + 410 = 820
The number of adenine (A) will be equal to the number of thymine (T).
Thus, A + T = Total number of nucleotides – Nucleotides containing G and C nitrogenous bases
= 1500 – 820 = 680
Therefore, A = 340 and T = 340
The number of adenine will be equal to number of thymine, which is 340.
Therefore, Number of pyrimidines that the segment possess = C + T
= 410 + 340 = 750
Answer:
UGA, UAA, and UAG
Explanation:
Each three-letter sequence of mRNA nucleotides corresponds to a specific amino acid, or to a stop codon. UGA, UAA, and UAG are stop codons
Hey cant see pic send it again