Question

What is the equation of the line described below written in slope-intercept form? the line passing through point (0, 0) and parallel to the line whose equation is 3x + 2y - 6 = 0

Answer 1

Answer:

The slope intercept form of the required line is $y=\frac{-3}{2}x$.

Step-by-step explanation:

If a line is defined as

$Ax+By+C=0$        ... (1)

Then the slope of the line is

$m=\frac{-A}{B}$

The given equation is

$3x+2y-6=0$       .... (2)

From (1) and (2), we get

$A=3, B=2, C=-6$

The slope of the line is

$m=\frac{-3}{2}$

The slope of parallel line is same. So, the slope of required line is -3/2.

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

The slope of required line is -3/2 and y-intercept is at (0,0).

$y=\frac{-3}{2}x+0$

$y=\frac{-3}{2}x$

Therefore the slope intercept form of the required line is $y=\frac{-3}{2}x$.

Answer 2

Y=-1.5x or y=-(3/2)x