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viktelen [127]
1 year ago
9

Write an inequality for the situation. At least 14 erasers are on the table.

Mathematics
2 answers:
frutty [35]1 year ago
3 0

Answer:

A

Step-by-step explanation:

I love these!

So, we know that the amount of erasers is at least 14. Which means it is greater than or equal to 14. We can write this like so: Number of erasers \geq 14

This is answer a

padilas [110]1 year ago
3 0

Answer:

The answer is c because greater can be also means higher

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Convert -3pi/10 to degrees
ipn [44]

we know there are 180° in π radians, how many degrees then in -3π/10 radians?

\bf \begin{array}{ccll} degrees&radians\\ \cline{1-2} 180&\pi \\\\ x&-\frac{3\pi }{10} \end{array}\implies \cfrac{180}{x}=\cfrac{\pi }{~~-\frac{3\pi }{10}~~}\implies \cfrac{180}{x}=\cfrac{\frac{\pi}{1} }{~~-\frac{3\pi }{10}~~} \\\\\\ \cfrac{180}{x}=\cfrac{\pi }{1}\cdot \cfrac{10}{-3\pi }\implies \cfrac{180}{x}=-\cfrac{10}{3}\implies 540=-10x\implies \cfrac{540}{-10}=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill -54=x~\hfill

5 0
4 years ago
What is the answer to this question
Lana71 [14]
CY is one third of SY; 33/3=CY; CY=11;
5 0
3 years ago
An English teacher has 6 short stories, 4 novels, and 23 poems to choose from. How many ways can he assign one of each to his cl
Karolina [17]

Answer:

552

Step-by-step explanation:

This is a problem of permutation which can be solved by rule of fundamental counting principle.

This principle states that if there "m" ways of doing one thing and "n" ways of doing other. Then no. of ways in which both the things can be done together is "m*n". This can be extended for m, n, p,r, s things and so on.

example: if there are 5 shirts and 3 trousers then number of ways in which the shirts and trousers can be worn is 5*3 = 15 ways.

_____________________________________________

The given problem is on similar concepts.

here  6 short stories, 4 novels, and 23 poems have to be assigned to his class.

Thus it can be done in 6*4*23 = 552 ways.

5 0
3 years ago
Find all real solutions<br> x + 5 = 14 - <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title="
rosijanka [135]
Multiply all terms by 2 to get rid of fractions
2x+10=28-x

Add x to both sides
3x+10=28

Subtract 10 from both sides
3x=18

Divide both sides by 3
x=6

Final answer: x=6
8 0
4 years ago
The average of the first 3 weights was 14 pounds. The average of the next 7 was 4 pounds. What was the overall average of the we
miskamm [114]

Answer:

Average = 10

Step-by-step explanation:

Given

First\ Three = 14 --- Average

Next\ Seven= 4 --- Average

Required

Determine the overall average

Represent the sum of the first three with x.

So:

\frac{x}{3} = 14

Solve for x

x = 14 * 3

x = 42

Represent the sum of the next seven with y.

So:

\frac{y}{7} = 4

Solve for y

y = 4 * 7

y = 28

The overall average is calculated as thus:

Average = \frac{x + y}{7}

Average = \frac{42 + 28}{7}

Average = \frac{70}{7}

Average = 10

7 0
3 years ago
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