3 years ago

Write the slope-intercept form of the equation

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

6 0

Y=-9/2x-13 is the line

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3 years ago

Evaluate each expression for w=5, x=3, y=4 and z=8.<br> 3y+6/2x

Aliun [14]

Plug in your numbers so the equation will turn out to be 3(4)+6/2(3) , you need to simplify 6/2 which will be 3 and 3 times 3 = 9 so the equation will be 3(4)+9 and 3 times 4 = 12 so the equation will now be 12+9 = 21
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3 years ago

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3 years ago

315 is what percent of 750?

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3 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

4 years ago