I need help w 20 - 7x = 6x

In a survey, three out of four students said that courts show too much concern for criminals. Of seventy randomly selected stude

vladimir1956 [14]

Answer:

B. Yes, because P(X ≥ 68) ≤ .05

Step-by-step explanation:

The probability of a score X occuring is said to be unusually high if the probability of a score of X or larger is lower than 5%.

For each student, there are only two possible outcomes. Either they think that the court shows too much concern for criminals, or they do not think this. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

Three out of four students said that courts show too much concern for criminals. This means that $p = \frac{3}{4} = 0.75$

Would 68 be considered an unusually high number of students who feel that courts are partial to criminals?

We have to find $P(X \geq 68)$ .

$P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 68) = C_{70,68}.(0.75)^{68}.(0.25)^{2} < 0.000001$

$P(X = 69) = C_{70,69}.(0.75)^{69}.(0.25)^{1} < 0.000001$

$P(X = 70) = C_{70,70}.(0.75)^{70}.(0.25)^{0} < 0.000001$

So

$P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70) < 0.000003$

$P(X \geq 68)$ is lower than 0.05, so this is an unusually high number.

So the correct answer is:

B. Yes, because P(X ≥ 68) ≤ .05

5 0

3 years ago

What is the measure of ∠FIH? A) 144° B) 90° C) 108°

vampirchik [111]

A) 144 degrees since it would be 72 x 2 I think

8 0

3 years ago

What is the probability that the mean duration of the 24 rowers with idna exceeds 63 minutes?

statuscvo [17]

Answer:

Step-by-step explanation:

Given that: Training-session duration of female rowers with normal iron status is Normally distributed, with mean 69 minutes and standard deviation 18minutes.

Solution:

z score shows the relationship between sample means. The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by the formula:

$z=\frac{x-\mu}{\sigma}\\\\for\ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} } \\\\where\ \mu=mean,\sigma=standard\ deviation,x=raw\ score$

Given that μ = 69 minutes, σ = 18 minutes, n = 24

For x > 63 minutes:

$z=\frac{x-\mu}{\sigma / \sqrt{n} } =\frac{63-69}{18/\sqrt{24} }=-1.63$

From the distribution table, P(x > 63) = P(z > -1.63) = 1 - P(z < 1.63) = 1 - 0.0516 = 0.9484

7 0

3 years ago

^please answer, thanks in advance ^

Rudiy27

Answer:

There is not enough information to determine the mean, the median is 28.

There is not enough information to determine the mean absolute deviation, the interquartile range is 18

Step-by-step explanation:

The box plot given has a skewed distribution, this means that both the mean and median values are not the same. From a box plot, the median value Can be obtained as the point in between the box.

From the box plot given, the marked point in between the box is 28 cm

Hence, Median = 28 cm

The mean cannot be inferred from the skewed box plot.

There is also not enough information to determine the mean absolute deviation ;

The interquartile range:

(Q3 - Q1)

Q3 = upper quartile, the endpoint of the box = 40

Q1 = the starting point of the box = 22

IQR = Q3 - Q1

IQR = 40 - 22 = 18

3 0

3 years ago

Noah is working on a geometry problem that involves finding the volume of a sphere with a diameter of 9 units. His work is shown

lesya692 [45]

No, Noah used the diameter instead of the radius in the calculations is the answer.

8 0

3 years ago

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I need help w 20 - 7x = 6x - 6