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11 months ago

Which angle is congruent to

Mathematics

1 answer:

kondor19780726 [428]11 months ago

5 0

The angle congruent to ∠CGD is the angle ∠AGF as they are vertical angles.

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PLEASE HELP!!!! What is 1+1

fiasKO [112]

2 because 1+1=2 and that’s why

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3 years ago

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Round 81065 to the nearest ten thousand, hundred, ten, and thousand

brilliants [131]

Ten thousand-80000
hundred-81100
ten-81070
thousands-81000

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3 years ago

WILL GIVE BRAINLIEST! PLEASE HELP ASAP!

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Evaluate using

PEMDAS

First we do what is inside of the Parenthesis 12 - 9 = 3

Now we have 2 + 3²

Next is Exponents 3² = 9

Now we have 2 + 9

there is no multiplication or division needed so we go straight to addition

9 + 2 = 11

So we can conclude that the answer is 11

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2 years ago

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Solve the equation N/-2=-15

otez555 [7]

Answer:

Step-by-step explanation:

N/-2=-15

N= -15 times -2

N= 30

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3 years ago

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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago