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1 year ago

The surface of the cerebral hemispheres consists of ridges and grooves. The shallow grooves are called ________.

2 answers:

7 0

Answer:
Sulci

Explanation:
The thin layers of cells cover the cerebral hemispheres called cerebral cortex. The elevated ridges of tissue on the surface of the cerebral cortex are known as gyri while the shallow grooves are termed sulci.

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Yuri [45]1 year ago

4 0

The surface of the cerebral hemispheres consists of ridges and grooves. The shallow grooves are called Sulci.

<h3>What is Cerebral Hemisphere?</h3>

The brain is formed by two cerebral hemispheres. It is separated by a groove called longitudinal fissure. The brain is divided into left and right cerebral hemispheres. These consist of an outer layer of gray matter called the cerebral cortex which is supported by an inner layer of white matter.

In placental mammals, the hemispheres are connected by the corpus callosum which is a very large bundle of nerve fibers.

There are three poles of the cerebral hemispheres:

1. The occipital pole

2. The frontal pole

3. The temporal pole

The thin layers of cells that cover the cerebral hemispheres are called the cerebral cortex. These raised ridges of tissue on the surface of the cerebral cortex are known as gyri while the shallower grooves are called sulci.

Thus, the surface of the cerebral hemispheres consists of ridges and grooves. The shallow grooves are called Sulci.

Learn more about Cerebral Hemisphere, here:

brainly.com/question/13543441

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The hershey chase experiment on bacteriophages showed the genetic information is carried in ____________.

Maksim231197 [3]

Answer:

The hershey chase experiment on bacteriophages showed the genetic information is carried in DNA.

Explanation:

In 1952 Alfred Hershey and Martha Chase provided evidence that DNA is the genetic material. These scientists carried out an experimental work with the T2 virus, a bacteriophage that infects the Escherichia coli bacteria, which reproduces by attaching itself to the outer wall of the bacteria, injecting its DNA into it where it replicates and directs, the synthesis of phage proteins. Phage DNA is encapsulated within proteins and produces phages, which lyse or break the cell and releasing phage from the progeny. They used radioactive forms (isotopes) of phosphorus and sulfur. A radioactive isotope can be used as a marker to identify the location of a specific molecule, because any molecule that contains the isotope is radioactive and therefore easy to detect. The DNA contains phosphorus, but doesn't contain sulfur, therefore phosphorus-32 was used to mark the DNA, instead the protein has sulfur, but not phosphorus, so sulfur-35 was used. Hershey and Chase found that sulfur-35 is outside the cell while phosphorus-32 was inside, indicating that DNA was the physical support of the inheritance. This work allowed the scientists to conclude that it's the DNA and not the protein that enters the bacteria during phage reproduction and that only the DNA is transmitted to the phage of the progeny.

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3 years ago

TIME PEM

Serggg [28]

The answer to this is D

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3 years ago

A 5-year-old boy has become increasingly lethargic for past 2 months. Bruising is noted on the skin of his lower legs. Hb 9.2 g/

mart [117]

Answer:

Acute Lymphoblastic Leukemia (ALL)

Explanation:

The 5 year old, male patient is most likely suffering from Acute Lymphoblastic Leukemia.

INTRODUCTION:

Acute Lymphoblastic Leukemia is also known as acute lymphocytic leukemia and acute lymphoid leukemia. It is the most common cancer of children.

This disease is marked by neoplasm composed by blast cells. Blast cells are immature B or T lymphocytes.

PATHOPHYSIOLOGY:

Blast cells are marked by scant cytoplasm, larger than usual nucleus, inconspicuous (small) nucleoli and delicate chromatin. These cells stain positive for Tdt marker ( terminal deoxynucleotidyl transferase). Tdt marker is absent in mature lymphocytes but present in immature lymphocytes and acute lymphoblastic leukemic cells. Majority of ALL cells stain positive for CALLA. CALLA stands for common acute lymphoblastic leukemia antigen. CALL is also known as CD 10 (cluster of differentiation 10).

The blast cells infiltrate the bone marrow and replace it. Since RBCs are produced by the bone marrow, pathological infiltration results in the decrease in the number of RBCs produced. This may manifest as anemia with decreased Hemoglobin concentration on complete blood count/ blood complete picture test. Platelet level will also be decreased due to bone marrow infiltration. Sometimes complete blood counts may reveal increased amounts of WBCs by counting immature blast cells as WBCs.

Decreased RBCs present as symptoms of anemia with patient complaining of fatigue and lethargy. Decreased platelet counts may result in bruising on skin as the ability to heal trivial wounds is decreased.

QUESTION:

Coming back to the question, there are many cues which point towards this diagnosis.

The age of the patient i.e. 5 years old implies us to consider pediatric diseases. ALL is the most common cancer occurring in children.

Lethargy warns us to consider anemia in the patient.

Bruising points towards decreased platelets in this patient. Low blood platelet count is called thrombocytopenia.

Hb 9.2 g/dL, Hct 27.8%, MCV 91 fL confirm anemia (Normal values in children; Hgb 11-13 g/dL, Hematocrit 34%, MCV 75-90 fL) and platelet count 101,000/µL establishes thrombocytopenia (normal platelet count is 150,000-450,000 per microliter). WBC count 12,128/µL is normal ( normal values in 4-7 years children 6,000-15,000 cells per microliter) in this patient.

Replacement of bone marrow by primitive cells with large nuclei, delicate chromatin; indistinct nucleoli with scanty cytoplasm is a typical feature of Acute Lymphoblastic Leukemia.

Positive staining for CALLA establishes acute lymphoblastic leukemia in this patient as this antigen is positive in ALL cells and this disease is also implied by the symptoms, history and laboratory tests of the patient.

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