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AlladinOne [14]
4 years ago
6

Can someone help me please? :)

Mathematics
1 answer:
DIA [1.3K]4 years ago
3 0
Webb High School spent about 1/3 if its budget on decorations
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If G(x) = 3x + 1, then G^-1(1) is
NISA [10]

One way in which to do this problem is to find the inverse function of G(x) first.  Another, faster, method is to look at G(x) = 3x + 1.  Find the x value for which y = 1:

1 = 3x + 1.  Then x must equal 0.  If (0, 1) satisfies G(x) = 3x + 1, then  (1, 0) satisfies the inverse function of G(x) = 3x + 1.  

Thus, the value of the inverse function with input 1 is 0.

Step 1:  Replace "G(x)" with y.

Step 2:  Solve the resulting equation for x.

Step 3:  Replace x with y and y with x.

                                                 -1

Step 4:  Replace this "y" with G    (x).  

Now replace "x" with "1".

7 0
4 years ago
*PLEASE ANSWER TY* What is the volume of this prism?
AveGali [126]

Answer: B. 23.9 cm³

Step-by-step explanation:

V = AH

A (area of the triangle base): 6×3÷2=9cm²

H (height of the prism): 2.65 cm

------------------------

V =  AH

V =(9) (2.65)

V = (23.85)

V= 23.85cm²

 ≈23.9

6 0
3 years ago
The figure shown is made of two rectangles.
Eddi Din [679]
198 is the answer ok ok ok
4 0
2 years ago
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Consider the system of inequalities and its graph. y ≤ –0.75x y ≤ 3x – 2 In which section of the graph does the actual solution
lora16 [44]
We need to assign a value for x to check the possible values of y. 1st inequality: y < -0.75x X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT 2nd inequality: y < 3x -2 X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT The actual solution to the system lies on the 4TH QUADRANT. </span>
3 0
3 years ago
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Find the mass. Volume=2.3cm cubed<br> Density=4.1g/cm cubed
Yakvenalex [24]
Density = mass / volume 
So if we know the density and volume, make an algebraic equation of this. 
4.1 = m ÷ 2.3 
Multiply each side by 2.3. 
9.43 = m 
The mass is 9.43 grams, hope this helps!
3 0
3 years ago
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