I’m pretty sure the answer is A
The solution for this problem is:
We know the problem has the following given:
Sample size of 200
X = 182
And the probability of .9005; computation: 1 - .0995 = .9005
So in order to get the probability:
P (x >= 182) = 1 – 0.707134 = .292866 is the probability
that when 200 reservations
are recognized, there are more passengers showing up than there
are seats vacant.
The other solution is:
p (>= 182) = p(183) +
P(184) + P(185) + ... + P(199) + P(200) = 0.292866
Answer:
Fruits: 107
Vegetables: 56.5
Step-by-step explanation:
Average is found by adding all of the values together and then dividing by the number of values that there are.
So for fruits, you would do 62+55+49+50+98+328 and then divide that whole thing by six.
Same for veggies, 34+122+57+21+79+26 with the answer divided by six.
Answer:
-4(3x+5)
Step-by-step explanation:
