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3 years ago

Question in pic........

Mathematics

1 answer:

MrMuchimi3 years ago

7 0

For this problem I think it is B

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Natasha is observing the growth of a population of bacteria. She started out with 250 bacteria cells. The population of bacteria

maxonik [38]

Y = 250 × 4x ... I think, I might be wrong.

4 0

3 years ago

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A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable

nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0

3 years ago

The length of a rectangle is 5 inches and the width is 7 inches. What is the area of

sashaice [31]

Answer:

35 inches

L×W=A

length×width=area

4 0

3 years ago

Read 2 more answers

Solve the equation<br> -3(x - 5) = 45

Olegator [25]

Answer:

x= -10

Step-by-step explanation:

Divide both sides by the numeric factor on the left side, then solve.

x = − 10

plz brainliest :'D

7 0

3 years ago

A manufacturer produces bolts of a fabric with a fixed width. A quantity q of this fabric (measured in yards) that is sold is a

BigorU [14]

Answer:

$R'(20) = 2000$

Step-by-step explanation:

We are given the following in the question:

Quantity, q

Selling price in dollars per yard, p

$q=f(p)$

Total revenue earned =

$R(p)=pf(p)$

f(20)=13000

This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.

f′(20)=−550

This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.

We have to find R'(20)

Differentiating the above expression, we have,

$R'(p) = \displaystyle\frac{d(R(p))}{dp} = \frac{d(pf(p))}{dp} = f(p) + pf'(p)$

Putting the values, we get,

$R'(p) = f(p) + pf'(p)\\\\R'(20) = f(20) + 20(f'(20))\\\\R'(20) = 13000 + 20(-550) = 2000$

7 0

4 years ago