All categories

3 years ago

Question in pic........

Mathematics

1 answer:

MrMuchimi3 years ago

7 0

For this problem I think it is B

You might be interested in

A 25-pound bag of fertilizer is on sale for $40. What is the price per ounce of the fertilizer?

REY [17]

Answer:

1.60

Step-by-step explanation:

6 0

1 year ago

PLEASE ANSWER THIS QUESTION RIGHT AND THE ANSWER CHOICES ARE IN THE ORDER.Which is the standard form of a quadratic equation?

sertanlavr [38]

Answer:

Its light blue (cyan).

Step-by-step explanation:

3 0

3 years ago

You sell soup mixes for a fundraiser. For each soup mix you sell, the company that makes the soup receives x dollars l, and you

Whitepunk [10]

Answer: $ 6

Step-by-step explanation:

Here, the cost price of each soup = x dollars

The cost price of 16 soup = 16 x

The selling price of 16 soup = 16 x + 96

Since, the total money received for 16 soup = The selling price of 16 soup - The cost price of 16 soup

= 16 x + 96 - 16 x

= 96

Thus, the total money received for 16 soup = 96 dollars

⇒ The total money received for 1 soup = $\frac{96}{16}$ dollars

⇒ The total money received for 1 soup = 6 dollars

Hence, for each soup 6 dollars is received.

7 0

3 years ago

Find the value of the variables please please help me out I will mark you the brainly! Please please

RSB [31]

Answer:

m = 54

Step-by-step explanation:

The secant- secant angle 20° is half the difference of the intercepted arcs, that is

$\frac{1}{2}$ (160 - 2m - 12) = 20° ( multiply both sides by 2 to clear the fraction )

- 2m + 148 = 40° ( subtract 148 from both sides )

- 2m = - 108 ( divide both sides by - 2 )

m = 54

4 0

3 years ago

Read 2 more answers

If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

$\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}$

$\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}$

This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

6 0

3 years ago