Below, the two-way table is given for a classof students.FreshmenSophomore Juniors Seniors TotalMale4622Female 3463TotalIf a mal
e student is selected at random, what is theprobability the student is a freshman.
1 answer:
<h2>Answer:</h2>
29%
<h2>Explanations:</h2>Probability is the likelihood or chance that ab event will occur. Mathematically;
Probability = Expected/Total
From the given table, the total number of male student is the total outcome as shown:
Total outcome = 4 +6+ 2 + 2
Total outcome = 14
If a male freshmen is selected at random, the expected outcome will be 4.
Determine the probability
Hence the probability that the male student is freshman is approximately 29%
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Answer:
n= -4
Step-by-step explanation:
First we have to find the equation of line which passes through (6,3) and (8,4).
Then we have to pass this line through the point (n , -2).
we know, equation of line passing through (x1,y1) and (x2,y2) is
So, the equation of line passing through (6,3) and (8,4) is
or,
multiplying both sides by -2
x-6=2(y-3)
or, x-6=2y-6
or, x-2y=6-6
or, x-2y=0
Now, we have to pass this line through (n,-2)
So, using the point in the line, that is using x=n , y=-2
we get
n-2(-2)=0
or, n+4=0
or, n=-4
Complete question is;
After examining daily receipts over the past year, it was found that the green parrot italian restaurant has been grossing over $2200 a day for about 85% of it's business days. Using this as a reasonably accurate measure, find the probability that the green parrot will gross over $2200:
A. At least 5 of the next 7 business days.
B. at least 5 of the next 10 business days.
C. less than 3 of the next 5 business days.
d. Exactly 7 of the next 10 business days
e. At least 1 of the next 5 business days.
Answer:
A) P(X ≥ 5) = 0.9262
B) P(X ≥ 5) = 0.9986
C) P(X ≤ 2) = 0.0266
D) P(X = 7) = 0.1298
E) P(X ≥ 1) = 0.9999
Step-by-step explanation:
This is a binomial probability distribution problem and as such we will use the formula;
P(X = k) = C(n, k) × p^(k) × (1 - p)^(n - k)
A. At least 5 of the next 7 business days will be;
P (X ≥ 5) = P(X = 5) + P(X = 6) + P(X = 7)
P(X = 5) = C(7, 5) × 0.85^(5) × (1 - 0.85)^(7 - 5)
P(X = 5) = 0.20965
P(X = 6) = C(7, 6) × 0.85^(6) × (1 - 0.85)^(7 - 6)
P(X = 6) = 0.396
P(X = 7) = C(7, 7) × 0.85^(7) × (1 - 0.85)^(7 - 7)
P(X = 7) = 0.320577
Thus;
P(X ≥ 5) = 0.20965 + 0.396 + 0.320577
P(X ≥ 5) = 0.9262
B. Probability of at least 5 of the next 10 business days will be;
P(X ≥ 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)
From online binomial calculator attached, we can see that the answer is;
P(X ≥ 5) = 0.9986
C. Probability of less than 3 of the next 5 business days will be;
P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)
From online binomial calculator attached, we can see that the answer is;
P(X ≤ 2) = 0.0266
D. Probability of exactly 7 of the next 10 business days will be;
P(X = 7) = C(10, 7) × 0.85^(7) × (1 - 0.85)^(10 - 7)
P(X = 7) = 0.1298
e. Probability of at least 1 of the next 5 business days will be;
P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)
From third image attached using online binomial calculator, we have;
P(X ≥ 1) = 0.9999
