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mihalych1998 [28]
3 years ago
10

Help help help plz ❤️Please

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer: #4 C   Domain is x such that x is greater than -1 (all real numbers greater than -1)

#5 B  Points C, F & G

Step-by-step explanation: Look at the coordinate of the vertex. It is at (-1, 1)  so the -1 is the lowest number in the Domain (running left to right). The attows at the right ends mean that the lines go to infinity. The symbol ∈ means "belongs to" the R (special font not available here) means "all real numbers.

The y-value, 1 is not relevant here, as the Range (up and down, like a mountain range) is infinity, and the arrows keep going forever. ∈R  means all real numbers.

For the Triangle: First ,imagine a box with the boundaries matching the domain and range given, so the left side is at -2, the right side is at 6 [Domain] and the  top and bottom are at 5 and -1 [Range]

Pick the points that are on the boundary lines.  C is at (6,3) on the right boundary, F is at (2,-1) on the bottom boundary and G is at (-2,5) at the corner where the top and left sides meet.

See the attachment below

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3 years ago
I'm confused. Can someone help?
VARVARA [1.3K]

a.

The polynomial w^2+18w+84 cannot be factored

The perfect square trinomial is w^2+18w + 81

----------

The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

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b.

The polynomial y^2-10y+23 cannot be factored

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---------

Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)

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