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fiasKO [112]
1 year ago
6

In parallelogram KLMN if MP=19 find MK

Mathematics
1 answer:
Oksanka [162]1 year ago
3 0

Given a parallelogram

Theorem: the diagonals of a parallelogram bisects each other

Thus

\begin{gathered} |MP|=|PK| \\ \text{therefore} \\ |MK|=|MP|+|PK| \end{gathered}\begin{gathered} \text{ |MP|=19} \\ \text{thus, |PK|=19} \\ |MK|=19+19=38 \end{gathered}

Hence, the measure of line MK is 38

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Which expressions are equivalent to 16x4 − 64? Check all that apply. 16x4 + 16x – 16x – 64 16x4 – 8x – 8x – 64 (4x2 + 8)(4x2 – 8
KengaRu [80]

Answer:

16x4 + 16x – 16x – 64

16x4 – 8x – 8x – 64

(4x2 + 8)(4x2 – 8)

16(x2 + 2)(x2 – 2)

7 0
3 years ago
A jar has 570 marbles of different colors.The ratio of red to blue marbles are 2:3 and red to green is 4:5.how many marbles of e
iVinArrow [24]

Answer:

The number of red marbles = 152

The number of blue marbles = 228 and

the number of green marbles = 190

Step-by-step explanation:

Let x be the number of red marbles, y be the number of blue marbles and z be the number of green marbles.

It is given that the total marbles = 570.

Therefore, x + y + z = 570 --- (1)

It is also given that the ratio of red to blue marbles is 2 : 3.

Therefore, x : y = 2 : 3

or 3x = 2y --- (2)

It is also given that the ratio of red to green marbles is 4 : 5.

Therefore, x : z = 4 : 5

or 5x = 4z --- (3)

From (2), y=\frac{3x}{2}

From (3), z=\frac{5x}{4}

Substituting the above in (1), we get,

x+\frac{3x}{2} +\frac{5x}{4} =570

Multiply both sides by 4.

4x + 6x + 5x = 2280

15x = 2280

Divide both sides by 15.

x = 152

Hence,

y = \frac{3(152)}{2}

y = 228

z = \frac{5(152)}{4}

z = 190

Therefore,

The number of red marbles = 152

The number of blue marbles = 228 and

the number of green marbles = 190

<u>Check:</u>

Total number of marbles = 152 + 228 + 190 = 570

Ratio of red to blue marbles = 152 : 228 = 2 : 3

Ratio of red t green marbles = 152 : 190 = 4 : 5


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3 years ago
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5 0
3 years ago
Helpp me plzzz!!
Alja [10]

Answer:

side angle side. Seems contrary

3 0
3 years ago
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