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1 year ago

How do you sketch a graph of a function?

Mathematics

1 answer:

Illusion [34]1 year ago

4 0

The graph of a function can be sketched by plotting points.

First and foremost, it is to be determined if the function is odd/even or periodic. Next, we find the x and y intercepts. To sketch a graph of a function, one can start by plotting a few points that lie on the graph using the coordinates given by the function. For example, if the function is y = x², then points (0, 0), (1, 1), and (2, 4) can be plotted by substituting the values of x into the function to find the corresponding values of y.

Subsequent to this, one can connect the points with a smooth curve to form the graph of function. If the function is a straight line, the graph will be a straight line. If the function is quadratic, the graph will be a parabola. The graph may take on a more complicated shape for more complex functions.

Read more about the graph of a function on:

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Write the ordered pairs relation

EastWind [94]

Answer:

There are no ordered pairs to relate too so i will tell the relation between a pair of numbers and a ordered pair.

Step-by-step explanation:

For an ordered pairs, each point is defined by 2 values.

7 0

3 years ago

Write an equation that can be used to answer each question

Ira Lisetskai [31]

1. (70 - 44) / 2

2. (45.00 - 25.50) / 6

3. (75 - 39) / 3

4. (90 - 30 +10) / 3

5. (100- 30+10) / 10

6. (50 - 5) / 10

PS: / means divide or division. also remember PEMDAS

Hope this helped you (;

4 0

3 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$

Now we have everything in order to replace into formula (1):

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

5 0

3 years ago

True or false. the points on a line can be paired one to one with real mumbers

frosja888 [35]

This is true, because there is an infinite amount of real numbers in both, and they are both countably infinite (so these infinities are equal). Hope this helps!

3 0

3 years ago

Read 2 more answers

Mike forgot to replace the cap on a bottle of room freshener. The room freshener began to evaporate at the rate of 15% per day.

Serggg [28]

For this case we have a function of the form:
$y = A * (b) ^ x
$
Where,
A: initial amount
b: decrease rate
x: time in days
Substituting values we have:
$y = 40 * (0.85) ^ x
$
Therefore, the graph of the function is a decreasing exponential function in the first quadrant and that has an initial value of 40.
Answer:
graph of exponential function going from left to right in quadrant 1 through the point 0, 40 and approaching the x axis

7 0

3 years ago