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3 years ago

Which of the following are valid names for the triangle below? Check all that

Mathematics

1 answer:

Tanya [424]3 years ago

5 0

Answer:

Explanation:

The first, third and fifth options are valid as it mentions the three edges; no matter what the order is as long as the three points are mentioned its considered as the valid name

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A triangle has a base that is increasing at a rate of 18 mm per minute with the height being held constant. What is the rate of

fomenos

Answer:

Step-by-step explanation:

Area of a triangle = 1/2 * base * height

A = 1/2bh

Rate of change of area is expresssed as dA/dt = dA/db * db/bt

db/dt is the rate at which the base is increasing.

Given db/dt = 18mm/min

A = 1/2*7b

A = 7b/2

dA/db = 7/2

The rate at which the area is changing dA/dt = dA/db * db/bt

dA/dt = 7/2 * 18

dA/dt = 7*9

dA/dt = 63mm/min

<em>Hence the rate at which the area of the triangle is changing is 63mm/min </em>

7 0

3 years ago

Need help with this..

Illusion [34]

Answer:

Step-by-step explanation:

m4 + m3 = 180 (Supplementary angle on 1 line)

m6 +m3 = 180 (Supplementary angle)

-> m6=m4

-> x+80 = 4x-10

-> 90 = 3x

-> x = 30

-> m6=m4 = 80+30 = 110

...

m1+m4 = 180 (Supplementary angle on 1 line)

-> m1 = 180 -110 = 70

3 0

3 years ago

Find the product. -8x5y2 · 6x2y

katrin [286]

Answer:

The product of the given expression $-8x^5y^2\times 6x^ 2y$ = 72x^6y^3[/tex]

Step-by-step explanation:

Given expression is $-8x^5y^2\times 6x^2y$

To find the product of the given expression:

The product of the given expression can be written as

$-8x^5 y^2\times 6x 2y=(-8x^5y^2)(6x^2y)$

$=(-8x^5y^2)(6x^2y)$

$=-48(x^5\times x^2)(y^2\times y^1)$ [since $a^m\times a^n=a^{m+n}$ ]

$=-48x^7y^3$

Therefore the product of the given expression $-8x^5y^2\times 6x^2y$ is $-48x^7y^3$

Therefore, $-8x^5y^2\times 6x^2y$ =-48x^7y^3[/tex]

3 0

3 years ago

Write an explicit formula for the sequence -13,-6,1,8, ...

dimulka [17.4K]

Answer:

7n-20 I believe

Step-by-step explanation:

hope this helps

4 0

3 years ago

Read 2 more answers

HELP PLEASE! Write a quadratic function that passes through the point (-1,9), has an axis of symmetry of x=-3 and a minimum valu

xxTIMURxx [149]

Answer:

$y = \frac{1}{2}x^{2} - 3x + 11.5$

Step-by-step explanation:

Vertex form of a quadratic equation;

$y = a( x - h )^{2} + k$

Vertex of the parabolas (h, k)

The vertex of the parabola is either the minimum or maximum of the parabola. The axis of symmetry goes through the x-coordinate of the vertex, hence h = -3. The minimum of the parabola is the y-coordinate of the vertex, so k= 7. Now substitute it into the formula;

$y = a ( x + 3 ) ^{2} + 7$

Now substitute in the given point; ( -1, 9) and solve for a;

$9 = a( (-1 ) + 3)^2 + 7\\9 = a (2)^{2} + 7\\9 = 4a + 7\\-7 -7\\2 = 4a\\\frac{1}{2} = a\\$

Hence the equation in vertex form is;

$y = \frac{1}{2}(x - 3)^{2} + 7$

In standard form it is;

$y = \frac{1}{2}x^{2} - 3x + 11.5$

7 0

3 years ago