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ICE Princess25 [194]
3 years ago
7

Suppose three riders rode a total of 182 miles. If they used a total of 13 horses, and rode each horse the same number of miles,

how many miles did they ride before replacing each horse? They rode _____ miles before replacing each horse. I REALLY NEED HELP
Mathematics
1 answer:
umka21 [38]3 years ago
5 0

Answer:

They rode 14 miles before replacing each horse

Step-by-step explanation:

We will be working under the assumption that all three riders sat on one horse at a time and rode it while the other horses rested.

From the problem, we can understand that the horses were each ridden for the same distance. This means that to get the total distance a horse rode before it was changed, we can divide the total distance by the number of horses that were used for the journey.

Distance each horse rode = 182/ 13 = 14 miles.

Therefore, each horse was ridden for 14 miles before it was changed.

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Gekata [30.6K]

Answer:

7,230,000,000 = 7.23 x 10 to the 9th power. 0.0000865 = 8.65 x 10 to the negative 5th power.

Step-by-step explanation:

7 0
3 years ago
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The following data was collected from a simple random sample of a population.
aivan3 [116]

Answer:

C

Step-by-step explanation:

This problem is analogous to the extraction of 6 elements from a total of 10 elements. It's the same if they are marbles, chips, or in this case, people, as here we don't care about the order of the selection as we only are drawing a sample.

Thus, the problem implies solving the amount of possible combinations of 10 people if we take by 6. There is a formula for this and is:

10 C 6 = 10!(6!4!)

If we operate, knowing that for any number x, x!=x*(x-1)*(x-2)*...*1

10 C 6 = 10!(6!4!) = 10*9*8*7*6*...*1 / [(6*5*...*1) * (4*3*2*1)]

10 C 6 = 10*9*8*7*6! / [(6*5*...*1) * (4*3*2*1)]

We have a 6! multiplying and another dividing, so they get eliminated, and as 4*2=8 and 9=3*3

10 C 6 = 10*9*8*7*/ [(4*3*2*1)] = 10*3*3*8*7*/ [(8*3*1)]

We can eliminate the 8s and one of the 3s on the numerator with the one on the denominator:

10 C 6 = 10*3*7*/1 = 210/1= 210

So, option C

5 0
3 years ago
Which graph below shows the solutions for the linear inequality ys x-3?
liraira [26]

Answer:

Graph A.

Step-by-step explanation:

Given the inequality: y\leq \dfrac{1}{4}x-3

Since the sign is "less than or equal to", the line cannot be dotted. Therefore, Options C and D are incorrect.

Since the sign is a "less than" sign, the required region must be below the line. Therefore, the graph which shows the given inequality is Graph A.

4 0
3 years ago
Finding angles , please help
jek_recluse [69]

Answer:

  • m∠C = 43.6°, m∠B = 107.4°, b = 51.2

Step-by-step explanation:

<u>Use the law of sines:</u>

  • a / sin ∠A = c / sin ∠C
  • 26 / sin 29° = 37 / sin ∠C
  • sin ∠C = 37 sin 29° / 26
  • sin ∠C = 0.6899
  • m∠C = arcsin 0.6899
  • m∠C = 43.6°

<u>Find the missing angle:</u>

  • m∠B = 180° - 29° - 43.6° = 107.4° (rounded)

<u>Use the law of sines to find the length of b:</u>

  • a / sin ∠A = b / sin ∠B
  • 26 / sin 29° = b / sin 107.4°
  • b = 26 sin 107.4° / sin 29°
  • b = 51.2 units (rounded)
8 0
2 years ago
The points (-7,-1) and (-8,6) fall on a particular line. What is its equation in point-slope form?
Arisa [49]

Answer:

y - 6 = -7(x + 8)

Step-by-step explanation:

Slope: m = (y2-y1)/(x2-x1) = (6 - -1)/(-8 - -7) = (6 + 1)/(-8 + 7) = 7/-1 = -7

Point-slope form: y - 6 = -7(x - -8)

=> y - 6 = -7(x + 8)

3 0
2 years ago
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