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goblinko [34]
1 year ago
10

Which graph represents a function? A coordinate plane shows 4 points with the following coordinates: (negative 3, 3), (negative

3, negative 3), (negative 1, 1), and (1, 4). A coordinate plane shows 4 points with the following coordinates: (negative 3, 3), (negative 2, negative 2), ( 1, 1), and (2, negative 2). A coordinate plane shows 4 points with the following coordinates: (negative 3, 3), (negative 3, negative 3), (1, negative 4), and (1, 1). A coordinate plane shows 4 points with the following coordinates: (negative 4, 4), (negative 4, 1), (negative 2, 1), and (2, 1).
Mathematics
1 answer:
Jet001 [13]1 year ago
4 0

The ordered pair that represents a function is:

⇒ (-3, 3), (-2, -2), (1, 1), (2, -2)

<u>What are Coordinates?</u>

A pair of numbers that describe the exact position of a point on a cartesian plane by using horizontal and vertical lines are called the coordinates.

The given points are;

(-3, 3), (-3, -3), (-1, 1), (1, 4)

(-3, 3), (-2, -2), (1, 1), (2, -2)

(-3, 3), (-3, -3), (1, -4), (1, 1)

(-4, 4), (-4, 1), (-2, 1), (2, 1)

Now, For an ordered pair to be a function, either of the following must be true:

Each x-value has exactly one corresponding y-value.

More than one x-values have the same corresponding y-values.

And, If any of the following conditions is true, then the ordered pair is not a function,

One x-value has multiple corresponding y-values.

More than one x-values have multiple corresponding y-values.

From the given options, only ordered pair  (-3, 3), (-2, -2), (1, 1), (2, -2) satisfies the condition to be a function.

Because none of its x-values have multiple corresponding y-values.

And, Other ordered pairs are either one-to-many or many-to-many.

So, The ordered pair that represents a function is:

⇒  (-3, 3), (-2, -2), (1, 1), (2, -2)

To learn more about ordered pairs visit:

brainly.com/question/19267542

#SPJ1

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dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
2 years ago
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