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dem82 [27]
3 years ago
10

43.12(bar on 12) in p/q form.​

Mathematics
1 answer:
arsen [322]3 years ago
4 0

Answer:

1423/33

Step-by-step explanation:

Let x = 43.121212.........

Two digits are repeating after decimal point. So multiply both sides by 100

100x = 4312.1212       --------------(I)

   <u> x =      43.1212  </u>   -----------(II)   { subtract equation (II) form (I)}

99x =      4269

x= 4269/99   {reduce to simplest form by giving by 3rd table}

x = 1423/33

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Gre4nikov [31]
There are probably mutliple solutions to this but heres one I found

x=0

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EXPLANTION

4-3(0) > 2(0)-1

4-0 > 0-1

4 > -1
3 0
3 years ago
(2xy-7)/3x+8=1 solve for y
Korvikt [17]
\frac{2xy - 7}{3x + 8} = 1
2xy - 7 = 3x + 8
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x(2y - 3) = 15
2y - 3 = \frac{15}{x}
2y = 3 + \frac{15}{x}
y = 1\frac{1}{2} + \frac{15}{2x}
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4 0
3 years ago
C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0
3 years ago
The table shows the distance Randy drove on one day of her vacation
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Given the table showing the distance Randy drove on one day of her vacation as follows:

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The rate at which she travels is given by

rate= \frac{distance}{time}  \\  \\ = \frac{55}{1} =55mi/h

If Randy has driven for one more hour at the same rate, the number of hours she must have droven is 6 hrs and the total distance is given by

distance = 55 x 6 = 330 miles.
4 0
3 years ago
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lilavasa [31]

Answer:

i think it is a but there are algebra caculators online

Step-by-step explanation:

7 0
3 years ago
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