Think of the equation of a linear function:
Recall y = mx + b for vertical shifts, we just add or subtract from 'b' and that will move the line up or down accordingly.. However, for horizontal shifts, we will need to add or subtract from 'x'. Note that the slope or 'm' stays the same for each type of shift.
Now that we know how the shifts occur, we might consider a different form of the equation for a linear function: y = a(x - h) + k here the 'a' is just our slope, 'k' is our original y intercept, and 'h' will represent the amount of horizontal shift.
So to get the desired transformations of a horizontal shift to the left of 8 and a vertical shift of down 3 from our original function y = x, we can make the following changes: y = (x + 8) - 3 Now you might be confused with how we got the 'x + 8'.. Let's consider values of 'h'. For positive values of h, the result will be a shift to the right and for negative values of h the result will be a shift to the left. So since we want a shift to the left we need to use a '-8' and when we substitute that into our new form, y = (x - h) + k you can see the sign change.
Now we can simplify of course and get the final equation: y = x + 5 or in function form f(x) = x + 5
In order for an equation to be in standard form, the equation has to be in Ax+By=c form, where A is equal to the coefficient of x and B is equal to the coefficient of y, whereas c is just the constant, or the number in the equation that isn't being multiplied to a variable. In this case, you should first distribute 2y into (x-1), and then you should perform inverse operations on terms on both sides of the equation such that one side of the equation will only have terms with x and y in them and the other side of the equation will only be a numerical value. When the equation is like this, then the equation is in standard form.
75% in fraction is 3/4 and the decimal is 0.75
