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kow [346]
1 year ago
9

Write an inequality using variables x and y whose graph is described by the given information. The points (2,5) and (-3,-5) lie

on the boundary line. The points (6,5) and (-2,-3) are solutions of the inequality.
Mathematics
1 answer:
luda_lava [24]1 year ago
8 0

The inequality using variables x and y which satisfy the points are; y>-3x+3.

<h3>What is inequality?</h3>

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

Given that the points (2,5) and (-3,-5) lie on the boundary line.

The system of inequality is given by:

y>-3x+3-

Now, the point that will lie in the solution set to the following system of inequality are the point that satisfies the inequality.

a)  (6, 5)

when x=6 and y= 5

then we have:

y>-3x+3

6 > -3×5 + 3

6>- 15+3

5 > -12

This means that the point will lie in the solution set.

Also, (-2, -3) when x= -2 and y= -3

then we have:

5 > -3×(-2) + 3

5> 6 + 3

5> 9

Hence, the inequality using variables x and y which satisfy the points are; y>-3x+3.

Learn more about inequality ;

brainly.com/question/14164153

#SPJ1

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What value of R makes r/ -11 = (-3) true
marissa [1.9K]

Answer:

The value of r=33 which makes the equation true.

Step-by-step explanation:

Given the equation

\frac{r}{-11}=-3

We have to find the value of r for which the equation must be true.

solving the equation

\frac{r}{-11}=-3

Multiply both sides by -11

\frac{r\left(-11\right)}{-11}=\left(-3\right)\left(-11\right)

r=33

Therefore, the value of r=33 which makes the equation true.

<u>VERIFICATION:</u>

Putting r=33 in the equation

\frac{r}{-11}=-3

\frac{33}{-11}=-3

-3=-3              ∵ \frac{33}{-11}=-3

L.H.S = R.H.S

Therefore, the value of r=33 which makes the equation true.

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we know that

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