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3 years ago

PLEASE HELPPPPPPPPPP solve for a b=Da+fa

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

b=d+f+a^2

b/D+f=a^2

Step-by-step explanation:

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There are 30 students in Mr.Thomas' class.If he wants 20% of the students in each group, how many students will be in. each grou

zhuklara [117]

First you find out what 20% of 30 is (30 * 0.20 = 6)
Then you take 30/6 to get your answer (30/6 = 5)
There will be 5 students in each group.

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3 years ago

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Which trigonometric ratio is correct for triangle DEF? (Hint: Use Pythagorean Theorem first) A.) Sin(D)= 24/7 B.) Tan(D)= 24/25

Tanya [424]

Answer:

Cos E= 24/25

Step-by-step explanation:

Length of hypotenuse: 7^2+24^2=625. 625 square root=25

Thus, DE is 25.

Sin D= 24/25, so that is false.

Tan D= 24/7, so that is false.

Cos E= 24/25, so that is true

Sin E= 7/25, so that is false.

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3 years ago

Given: 3x + 1 = -14; Prove: x = -5<br> Statements

WINSTONCH [101]

Step-by-step explanation:

3x + 1 = -14

3x = -14 - 1

3x = -15

x= -15÷3

x= -5

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3 years ago

Which of the following sets of lengths can be used to form the sides of a triangle? Explain your reasoning.

Bad White [126]

Answer:A can be use to form a triangle.

Step-by-step explanation:

a+b>C

5+18 >20

23>20

SO this is a triangle since if you add A and B together it is greater than C.

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3 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

3 years ago