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marishachu [46]
1 year ago
5

Each sequence has eight terms. Evaluate each related series. 1,-1,-3, . . . . . . -13

Mathematics
1 answer:
o-na [289]1 year ago
8 0

The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48

The given sequence is:

1,-1,-3,  . . -13

and there are 8 terms.

The related series of this sequence is:

1-1-3-5- ... -13

Notice that the series is an arithmetic series with:

first term, a(1) = 1

common difference, d = -1 - (1) = -2

last term, a(8) = -13

To find the sum of the series, use the sum formula:

S(n) = n/2 [(a(1) + a(n)]

Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:

S(8) = 8/2 [1 + (-13)]

S(9) = 4 . (-12) = -48

Learn more about sum of a series here:

brainly.com/question/14203928

#SPJ4

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2 *       2 and 3/4.

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2 * 11/4 =   22 / 4 =   5 and 2/4

= 5 and 2/4  or   5 and 1/2 or   5.5

Hope this helps.
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3 years ago
Please help quickly.<br> Find the measure of the unknown angle
Vladimir [108]

Answer:

65

Step-by-step explanation:

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2 years ago
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If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
Leokris [45]

Answer: The value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

Step-by-step explanation:

Since we have given that

y varies directly as x.

If y = 18, when x = 5.

So, we need to find the value of y when x is 11.

According to question, we get that

\dfrac{y}{x}=\dfrac{18}{5}=\dfrac{y}{11}\\\\18\times 11=5y\\\\198=5y\\\\\dfrac{198}{5}=y\\\\y=39.6

Hence, the value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

5 0
3 years ago
Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar
Maurinko [17]

Answer:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

\bar X = 94.2

The standard deviation is given by:

s= 15.5

And the standard error is given by:

SE = \frac{s}{\sqrt{n}} =3.1

And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

z_{\alpha/2}= \pm 0.994

We can find the interval like this:

\bar X \pm ME

And replacing we got:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

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gtnhenbr [62]

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Step-by-step explanation

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