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Luden [163]
3 years ago
8

I need to see how to work this problem 6-(-7)=

Mathematics
2 answers:
GaryK [48]3 years ago
7 0
Hello there! The answer would be:13

Remember ⬇️

Positive & positive = positive

Negative & positive = negative

Positive & negative = negative

Negative & negative = positive

For problems like this, you can use a number line! =)

Good luck on your assignment and enjoy your day!

~MeIsKaitlyn:)
alisha [4.7K]3 years ago
3 0
Hi there!

Here is what the rules says

+ * + = +  (Plus times plus = plus)
+*- = - (Plus times minus = minus)
- * - = + (Minus times minus = Plus
- * + = -  (minus times plus = minus)

You need to know the rules by heart because you will use it a lot.

So let see how it works with the problem

6 -(-7)
What does the rules say? It says
- * - = plus  
So, we gonna use PLUS for the sign
6-(-7) = 6 + 7 = 13

13 is the correct answer.

I hope I helped. Please let me know if you have more questions.
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How to do graphs of quadratic functions ​
Anastaziya [24]

Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

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3 years ago
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lakkis [162]

Answer:

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8 0
3 years ago
Read 2 more answers
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