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Anni [7]
1 year ago
11

Write the number below (81) as a power with a base of 3 and a base of 9

Mathematics
1 answer:
likoan [24]1 year ago
5 0

Answer:

base of 3 --> 3^4 (three to the fourth); base of 9 --> 9^2 (nine squared)

Step-by-step explanation:

<u>3 x 3</u> = 9 x <u>3</u> = 27 x <u>3</u> = 81 = 3^4

You multiply 3 by itself 4 times.

<u>9 x 9</u> = 81 = 9^2

You multiply 9 by itself 2 times.

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Given circle Q with a measure of SR=120° and a radius of 9 feet, as shown below.
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The arc length of the entire circle would be 2*PI*9

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5 0
3 years ago
Please help do this
aalyn [17]

Answer:

<h3>1)m+5q=1+5x5 =26</h3><h3>2)(y-x^3)=3-1^3 =3-1 =2</h3><h3>3)q(p+2)=3(3+2) =3(5) =15</h3><h3>4)y+y-x=5+5-6 =10-6 =4</h3><h3>5)(z+y)÷6=6+6÷6 =2</h3><h3>6)h(j-h)=3(6-3) = 3x3=9</h3><h3>7)x+y+y = 5+2+2=9</h3><h3>8)z^2-y =9-4=5</h3><h3>9)b(4+a)=2(4+6) =2x10 =20</h3><h3>10)m-n+m =5-1+5 = 4+5 =9</h3><h3>11)(h+j)÷6 = (2+4)÷6 = 1</h3>

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5 0
3 years ago
Write all three forms (slope intercept, point slope and standard) of a line containing the points (4, -11/3) and (1/2, -29/6).
Zanzabum

Answer:

See explanations below

Step-by-step explanation:

Slope intercept form of the equation is expressed as y = mx+b

m is the slope

b is the intercept

Given the coordinates (4, -11/3) and (1/2, -29/6)

Slope m = -29/6-(-11/3)÷(1/2-4)

m = (-29/6+11/3)÷(-7/2)

m = -29+22/6÷(-7/2)

m = -7/6÷(-7/2)

m = -7/6×2/-7

m = 2/6

m = 1/3

Get the intercept b

Substitute m= 1/3 and (4, -11/3) into y = MX+b

-11/3 = 1/3(4)+b

-11/3 = 4/3+b

b= -11/3-4/3

b= -15/3

b =-5

Get the required equation

y = 1/3 x -5 (slope-intercept form)

Point slope form of the equation is expressed as y-y0 = m(x-x0)

Substituting m = 1/3 and the point (4,-11/3)

x0 = 4

y0 = -11/3

y - (-11/3) = 1/3(x-4)

y+11/3 = 1/3(x-4) (point-slope form)

For standard format

Recall that y = 1/3x - 5

Multiply through by 3

3y = 1/3x(3)-5(3)

3y = x-15

3y-x = -15(standard form)

3 0
3 years ago
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