Answer:
2 to the power of one sixth
Step-by-step explanation:
Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:
![\sqrt[n]{x} = {x}^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D%20)
So you can rewrite the given fraction as

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

Since

the answer is
![{2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B6%7D%20%7D%20%20%5C%3A%20or%20%5C%3A%20%20%5Csqrt%5B6%5D%7B2%7D%20)
Answer:
<h2>A</h2>
Step-by-step explanation:
<em><u>e5uiitweyutwwsuoye34t</u></em>
Answer:
2^0+2^1+2^2+...+2^49
Step-by-step explanation:
1=2^0
2=2^1
4=2^2
8=2^3
and so on
Answer:
No not all right angles are congruent.
Step-by-step explanation:
Answer:
Some of the possible factorizations of the monomial given are:


Step-by-step explanation:
To factorize the monomia you need to express it as a product of two or more monomials. Therefore, you must apply the proccedure shown below:
- Descompose into prime numbers:

- Then, keeping on mind that, according to the Product of powers property, when you have two powers with equal base you must add the exponents, you can make several factorizations. Below are shown some of the possible factorizations of the monomial given:

