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Ostrovityanka [42]
3 years ago
5

Angle PQRPQR and angle TQVTQV are vertical angles. The measures of the two angles have a sum of 100^{\circ}100

Mathematics
2 answers:
Kitty [74]3 years ago
7 0
10005ssduduc Vicdhdjdjd
Aneli [31]3 years ago
4 0

Answer:

same question

Step-by-step explanation:

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Max and Sven bike away from home in the same direction starting at noon. They bike at constant speeds. Max bikes at xmph and he
bagirrra123 [75]

Answer:

(xy)4

Step-by-step explanation:

x * y will give the distance in 1 hr and if you multiply by 4 it will give the distance od 4 hr.

3 0
2 years ago
(15 point) Solve for 14 and 16! The answer could be 58, 11, or 15 for either one. If u get something different let me know.
aksik [14]

Answer:

14. 58 degrees

16. 11 degrees

Step-by-step explanation:

14. The sum of all 3 interior angles of a triangle is 180. We know right angles are 90 degrees. So 180 - 90 - 32 = 58 degrees

16. When two parallel lines are cut by a transversal, the corresponding angles have the same measure. So the angle above angle a has the same measure as the 169 degree angle in the same position on the other line. I hope those words make sense. Then angle a and the angle above it (which we know = 169 degrees) combine to make a straight line/straight angle, which = 180 degrees. 180- 169 = 11

Please let me know if you have questions.

8 0
2 years ago
If x = 3 what is the value of x squared x
ololo11 [35]
3^2 is equal to 9 and that is the right answer
4 0
3 years ago
Any help with an explanation would be appreciated!
Lilit [14]

Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)

h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
5 0
2 years ago
Can someone help me plz...
S_A_V [24]

Answer:

60 475

95 570

130 700

Step-by-step explanation:

subtract 95 from 60 then get that solution and add it to 95. then get 700 and subtract it from 130 then youll get 570 then subtract it again.

3 0
3 years ago
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