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1 year ago

15

Perform the following division and write the quotient in trigonometric form. Write the magnitude in exact form. Write the argume

nt in radians and round it to twodecimal places if necessary.

1 answer:

Tema [17]1 year ago

3 0

$\text{ }\frac{-4\text{ - 2i }}{\text{ 3 + 2i}}$

Let's apply the Complex Arithmetic Rule:

$\frac{a+bi}{c+di}\:=\:\frac{\left(c-di\right)\left(a+bi\right)}{\left(c-di\right)\left(c+di\right)}\:=\:\frac{\left(ac+bd\right)+\left(bc-ad\right)i}{c^2+d^2}$

We have: a = -4, b = -2, c = 3 & d = 2

$\frac{\left(-4\cdot \:3+\left(-2\right)\cdot \:2\right)+\left(-2\cdot \:3-\left(-4\right)\cdot \:2\right)i}{3^2+2^2}$ $\frac{(-12\text{ - 4\rparen + \lparen-6 + 8\rparen i}}{9\text{ + 4}}$ $\frac{-16+2i}{13}$

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Find f(b-2) if f(x) = x^2-6x+1

jasenka [17]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equivalent expression is ~

$f(b - 2) = {b}^{2} - 10b + 17$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's evaluate f(b - 2) ~

$f(x) = {x}^{2} - 6x + 1$

$f(b - 2) = (b - 2) {}^{2} -6 (b - 2) + 1$

$\mathcal{ {f(b - 2) = {b}^{2} + 2 {}^{2} - (2 \times b \times 2) - 6b + 12}}$

$f(b - 2) = {b}^{2} + 4 - 4b - 6b + 12 + 1$

$f(b - 2) = {b}^{2} - 10b + 17$

4 0

2 years ago

Read 2 more answers

A human resource manager wants to see if there is a difference in the proportion of minority applicants who get the job and the

mash [69]

Answer:

Error Bound = 0.04

Step-by-step explanation:

Whenever we want to estimate parameter from a subset (or sample) of the population, we need to considerate that your estimation won't be a 100% precise, in other words, the process will have a random component that prevents us from always making the exact decision.

With that in mind, the objective of a confidence interval is to give us a better insight of where we expect to find the "true" value of the parameter with a certain degree of certainty.

The estivamative of the true difference between proportions was -0.19 and the confidence interval was [-0.23 ; -0.15].

The question also defines the error bound, as the right endpoint of the confidence interval minus the sample mean difference, so it's pretty straight foward:

Error Bound = $-0.15 -(-0.19) = -0.15 + 0.19 = 0.04$

The interpretation of this would be that we expect that the estimative for the difference of proportions would deviate from the "true" difference about $\pm 0.04$ or 4%.

6 0

3 years ago

In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.

Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

$\bar x = A + \frac{\sum fd}{\sum f}$

Where $\bar x$ is the mean

A is the assumed mean

From the given information,

$\bar x = 80$

$A = 60$

$\sum f = 40$

Putting the parameters into the equation, we get

$80 = 60 + \frac{\sum fd}{40}$

$80-60 = \frac{\sum fd}{40}$

$20 = \frac{\sum fd}{40}$

$\sum fd = 20 \times 40$

$\sum fd = 800$

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

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8 0

2 years ago

What is the quotient of m^6/5 divided by 5/m^2

DENIUS [597]

Answer:

$\large\boxed{\dfrac{m^8}{25}}$

Step-by-step explanation:

$\dfrac{m^6}{5}\div\dfrac{5}{m^2}\\\\\text{Divide by a fraction is the same as multiply by its reciprocal}\\\\=\dfrac{m^6}{5}\times\dfrac{m^2}{5}=\dfrac{m^6\times m^2}{5\times5}\\\\\text{use}\ a^n\times a^m=a^{n+m}\\\\=\dfrac{m^{6+2}}{25}=\dfrac{m^8}{25}$

3 0

3 years ago

Emma has $89 in her bank account. she uses 30% of her money to pay a bill. How much did she spend?

Alexxandr [17]

The answer is c 10% of 89 is 8.9 so multiply by 3 you get 26.70

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3 years ago

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