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lukranit [14]
2 years ago
5

Find f(b-2) if f(x) = x^2-6x+1

Mathematics
2 answers:
Anit [1.1K]2 years ago
8 0

Answer:

b^2-10b+ 17

Step-by-step explanation:

f(b-2) = (b-2)^2-6(b-2)+ 1

= b^2 + 4 - 4b -6b + 12 +1

=b^2-10b+ 17

jasenka [17]2 years ago
4 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent expression is ~

  • f(b - 2) =  {b}^{2}  - 10b + 17

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's evaluate f(b - 2) ~

  • f(x) =  {x}^{2}  - 6x + 1

  • f(b - 2) = (b - 2) {}^{2}  -6 (b - 2) + 1

  • \mathcal{ {f(b - 2) =  {b}^{2}   +  2 {}^{2}  - (2 \times b \times 2) - 6b + 12}}

  • f(b - 2) =  {b}^{2}   + 4 - 4b - 6b + 12 + 1

  • f(b - 2) =  {b}^{2}  - 10b + 17
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<em>Note:</em>

<em>Your first question is missing the y-intercept, so I am solving the 2nd question. You would still get your concept clear because the procedure to solve each of the questions is the same.</em>

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