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1 year ago

The measure of an angle is 44.6°. What is the measure of its complementary angle?

Mathematics

1 answer:

Leni [432]1 year ago

7 0

The measure of the complementary angle to the angle 44.6° as given in the task content is; 45.4°.

<h3>What is the measure of the complementary angle as given in the task content?</h3>

It follows from the task content that the complementary angle to angle measure 44.6° be determined.

Unlike supplementary angles which add up to 180, complementary angles add up to 90°.

Hence, the required complementary angle is; 90°-44.6° = 45.4°.

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The average age at which adolescent girls reach their adult height is 16 years. Suppose you have a sample of 27 adolescent girls

abruzzese [7]

Answer:

a) t-statistic t = 0.9532

b) The standard error S.E = 1.2

c) The new t-statistic = 1.95

d) The new estimated standard error =0.666

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 16

The sample size n=27

The mean of the sample = 17.1

Given that the variance of the sample (S²) = 36.0

The standard deviation of the sample (S) = √36 = 6

Test statistic

$t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$t = \frac{17.1 -16}{\frac{6}{\sqrt{27} } }$

t = 0.9532

The standard error is defined by

$S.E = \frac{S.D}{\sqrt{n} } = \frac{6}{\sqrt{27} } =1.154$

Step(ii):-

c) given that the sample size n = 81

Test statistic

$t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$t = \frac{17.1 -16}{\frac{6}{\sqrt{81} } }$

t = 1.65

The new standard error is defined by

$S.E = \frac{S.D}{\sqrt{n} } = \frac{6}{\sqrt{81} } = 0.66$

3 0

2 years ago

A farmer stores bags of seed in 4 rows. There are 4 bags

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Answer:

16 bags in all

Step-by-step explanation:

4x4=16

5 0

2 years ago

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Find the LCD of the fractions, and then simplify the expression. Assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3

tamaranim1 [39]

The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-

5(2y^2) - 4(x)
------------------
6x^2y^3

= 2( 5y^2 - 2x)
-----------------
6x^2y^3

= 5y^2 - 2x
-----------
3x^2y^3

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3 years ago

Find K by evaluating Limit

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

$\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4$

{L'Hospital's rule}

I hope this helps you

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2 years ago

Linda walked 1/6 mi to the park and then another 4/9 mi to the cafe. How far did she walk in total?

Musya8 [376]

Answer:

could you show the answers

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