The numbers are: "7 " and "21 " .
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Explanation:
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The numbers are: "x" and "x + 14" .
x + (x + 14) = 28 . Solve for "x" ; and then solve for "x + 14" .
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→ x + (x + 14) = 28 ;
Rewrite as:
→ x + x + 14 = 28 ;
→ 1x + 1x + 14 = 28 ;
→ 2x + 14 = 28 ;
Subtract "14" from each side of the equation;
→ 2x + 14 − 14 = 28 <span>− 14 ;
</span> → 2x = 14 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = 14 / 2 ;
→ x = 7 .
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So; one of the numbers is: " 7 " .
The other number is: " x + 14 " ; which equals: " 7 + 14 = 21".
The other number is: "21 " .
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The numbers are: "7 " and "21 " .
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Answer:
Step-by-step explanation:
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The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
<h3>How to determine the number of ways</h3>
Given the word:
ESTABROK
Then n = 8
p = 6
The formula for permutation without restrictions
P = n! ( n - p + 1)!
P = 8! ( 8 - 6 + 1) !
P = 8! (8 - 7)!
P = 8! (1)!
P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1
P = 40, 320 ways
Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
Learn more about permutation here:
brainly.com/question/4658834
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X (X - 1) = 342
x² - x = 342
x² - x - 342 = 0
X = 19
