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Nimfa-mama [501]
3 years ago
7

(3x3 – x2 – 2x - 10) = (x - 2) 2 si

Mathematics
1 answer:
GREYUIT [131]3 years ago
6 0
2 is the correct answer
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Forty-five people were asked about how many miles they walked in one week. The results are shown in the graph. What is the mean
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I dont know exactly your answer but ill tell you how to solve add all your numbers together and then divide it by 45 (the number of numbers u have)
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PLSSS HELP ME!! I'll give you 20 points and the brainlest answer.​
MrMuchimi
The answer should be this;
11.5(7) + 10.7 (8)= 166.1

166.1+ 85.6=251.7
8 0
3 years ago
How many atoms sodium would a 4 mole sample of Na3P have?
ioda
<h3>Answer:</h3>

2 × 10²⁴ atoms Na₃P

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Step-by-step explanation:</h3>

<u>Step 1: Define</u>

4 mol Na₃P

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 4 \ mol \ Na_3P(\frac{6.022 \cdot 10^{23} \ atoms \ Na_3P}{1 \ mol \ Na_3P} ) = 2.4088 × 10²⁴ atoms Na₃P

<u>Step 4: Check</u>

<em>We are given 1 sig fig. Follow sig fig rules and round.</em>

2.4088 × 10²⁴ atoms Na₃P ≈ 2 × 10²⁴ atoms Na₃P

7 0
3 years ago
What is (-38) + what = -149?
lbvjy [14]

Answer:

(-111)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
in 2009 a total of R36 000 was invested in two accounts. One account earned 7% annual interest and the other earned 9% .The tota
Akimi4 [234]

a = amount invested at 7%

b = amount invested at 9%

we know the amount invested was ₹36000, thus we know that whatever "a" and "b" are, a + b = 36000.  We can also say that

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of a}}{\left( \cfrac{7}{100} \right)a}\implies 0.07a~\hfill \stackrel{\textit{9\% of b}}{\left( \cfrac{7}{100} \right)b}\implies 0.09b

since we know the interest earned from the invested was ₹2920, then we say that 0.07a + 0.09b = 2920.

\begin{cases} a + b = 36000\\\\ 0.07a+0.09b=2920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{a + b = 36000\implies \underline{b = 36000-a}}~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.07a~~ + ~~0.09(\underline{36000-a})~~ = ~~2920} \\\\\\ 0.07a+3240-0.09a=2920\implies 3240-0.02a=2920\implies -0.02a=-320 \\\\\\ a=\cfrac{-320}{-0.02}\implies \boxed{a=16000}~\hfill \boxed{\stackrel{36000~~ - ~~16000}{20000=b}}

5 0
3 years ago
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