The answer is 1.87 pounds heavier. This is found out by subtracting 2.8 from 4.67.
Hope this helps!
Answer:
The largest side of given triangle is: AB
Step-by-step explanation:
In order to find the largest side, we have to find all the triangles first.
The two angles at point A will sum up to 180° as the angles on the straight line are supplementary.
So,
∠A = 44°
∠C = 71°
The sum of interior angles of a triangle is 180°
Using this:
∠A+∠B+∠C = 180°
44°+∠B+71° = 180°
∠B+115° = 180°
∠B = 180°-115°
∠B = 65°
In a triangle, the side opposite to the largest angle is the largest. In the given triangle, ∠C is the largest so the side AB which is opposite to ∠C is the largest.
Hence,
The largest side of given triangle is: AB
Use cosine rule,
cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)
cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)
cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)
Check:29.926+56.251+93.823=180.0 degrees....ok
Answer: 4/18
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Required:
Calculate the angle between u and v
The angle is calculated as thus:
For a vector
becomes
For a vector
So;
So:
Take arccos of both sides
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