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weeeeeb [17]
1 year ago
6

Unproctored Placement ASThe quadrilaterals JKLM and PQRS are similar.Find the length x of PQ.JM=5, PS=4.5, JK=3.35K4.5PheHO1.8

Mathematics
1 answer:
Pachacha [2.7K]1 year ago
6 0

Given that the quadrilaterals are similar, we know that:

\frac{JM}{JK}=\frac{PS}{PQ}.

Substituting the given values, we get:

\frac{5}{4.5}=\frac{3}{x}.

Solving the above equation for x, we get:

\begin{gathered} 5x=3(4.5), \\ x=\frac{3(4.5)}{5}. \end{gathered}

Simplifying the above result, we get:

x=2.7

<h2>Answer:</h2>x=2.7

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I think the answer is $4.92.

Step-by-step explanation:

Although the answer seems a little unreasonable, I think this is the answer:

$82 * 60% = $49.2

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8 0
2 years ago
20 - 4x = 2(4 - 8x) This needs solving
Olenka [21]

20 - 4x = 2(4 - 8x)

Make sure to do the parentheses first or factor out first

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add 16x to both sides

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3 years ago
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Marlon asks a friend to think of a number from 5-11. What is the probability that marlins friend will think of the number 9
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Answer:

14.29% probability that Marlon's friend will think of the number 9

Step-by-step explanation:

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4 0
3 years ago
Can you help me i dont know thw anwser
Margaret [11]

\text{Let the side of square 1, square 2 and square 3 be x, y and z respectively.}\\\\\text{Given that,}\\\\\text{Perimeter of square 1,~~ p  =100 units.}\\\\\text{So}~ x=\dfrac p 4 =  \dfrac{100}4 =25~\text{units.}\\\\\\\text{Area of square 2, a = 225 units}^2\\\\\text{So}~y = \sqrt{a} = \sqrt {225} = 15~ \text{units.}\\\\\text{Use Pythagorean theorem to find z}^2\\\\x^2 =y^2 +z^2 \\\\\implies 25^2 = 15^2 +z^2\\\\\implies z^2 = 625 - 225 = 400\\\\\\

\text{Hence the area of square 3 is 400 units}^2.

8 0
3 years ago
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