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weeeeeb [17]
1 year ago
6

Unproctored Placement ASThe quadrilaterals JKLM and PQRS are similar.Find the length x of PQ.JM=5, PS=4.5, JK=3.35K4.5PheHO1.8

Mathematics
1 answer:
Pachacha [2.7K]1 year ago
6 0

Given that the quadrilaterals are similar, we know that:

\frac{JM}{JK}=\frac{PS}{PQ}.

Substituting the given values, we get:

\frac{5}{4.5}=\frac{3}{x}.

Solving the above equation for x, we get:

\begin{gathered} 5x=3(4.5), \\ x=\frac{3(4.5)}{5}. \end{gathered}

Simplifying the above result, we get:

x=2.7

<h2>Answer:</h2>x=2.7

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1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
3 years ago
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