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Diano4ka-milaya [45]
1 year ago
5

Help me answer as soon as possible, thank you!A and B only

Mathematics
1 answer:
MArishka [77]1 year ago
3 0

Answer:

(a)4

(b)7

Explanation:

Given f(x) and g(x) defined below:

\begin{gathered} f(x)=\{(3,2),(5,1),(7,4),(9,3),(11,5)\} \\ g(x)=\{(1,3),(2,5),(3,7),(4,9),(5,11)\} \end{gathered}

(a) f(g(3))

\begin{gathered} g(3)=7 \\ f\lbrack g(3)\rbrack=f(7)=4 \\ \implies f\lbrack g(3)\rbrack=4 \end{gathered}

The value of f(g(3)) is 4.

(b) (g o f)(9)

\begin{gathered} (g\circ f)(9)=g\lbrack f(9)\rbrack \\ f(9)=3 \\ g\lbrack f(9)\rbrack=g(3)=7 \\ \implies(g\circ f)(9)=7 \end{gathered}

The value of (g o f)(9) is 7.

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-1/5c+2+c=1/5(10c-20)
Andreyy89

Let's solve your equation step-by-step.

(− 1 /5 )(c)+2+c= 1 /5  (10c−20)

Step 1: Simplify both sides of the equation.

(− 1 /5 )(c)+2+c= 1 /5 (10c−20)

(− 1 /5 )(c)+2+c=( 1 /5 )(10c)+( 1 /5 )(−20) (Distribute)

−1 /5 c+2+c=2c+−4

( −1 /5 c+c)+(2)=2c−4 (Combine Like Terms)

4 /5 c+2=2c−4

4 /5 c+2=2c−4

Step 2: Subtract 2c from both sides.

4/5 c+2−2c=2c−4−2c

−6 /5 c+2=−4

Step 3: Subtract 2 from both sides.

−6 /5 c+2−2=−4−2

−6 /5 c=−6

Step 4: Multiply both sides by 5/(-6).

( 5 /−6 )*( −6 /5 c)=( 5 /−6 )*(−6)

c=5

Answer:

c=5

7 0
3 years ago
A pitcher coming back from an injury limits the number of pitches thrown in bull pen sessions as shown.
yKpoI14uk [10]

Answer:

3

Step-by-step explanation:

6 0
2 years ago
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Pls do so this geometry problem been difficult and need the answer who knows how to do this 100% answer
gulaghasi [49]

Answer:

16

Step-by-step explanation:

Since line CE is equal to 32 and line DB is the bisector (cut into the middle) of line CE then line CF would be half of line CE. Hence the reason that line CF is equal to 16

4 0
3 years ago
A penny falls from the top of Hard Rock Stadium The height of the penny after a seconds is given by f(x) = 350 - 16x²
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Step-by-step explanation:

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3 years ago
System of conics help
ZanzabumX [31]

Answer:

Solutions are (6,3) and (-2,3).

Step-by-step explanation:

From the first equation given we can write:

(x-2)^{2} = 16-(y-3)^{2}\\  

substituting for (x-2)^{2} in the second equation given we get

\frac{16-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} = 1

\frac{-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} =0

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Putting y=3 in the first equation we get

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7 0
3 years ago
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