Let's solve your equation step-by-step.
(−
1
/5
)(c)+2+c=
1
/5 (10c−20)
Step 1: Simplify both sides of the equation.
(−
1
/5
)(c)+2+c=
1
/5
(10c−20)
(−
1
/5
)(c)+2+c=(
1
/5
)(10c)+(
1
/5
)(−20) (Distribute)
−1
/5
c+2+c=2c+−4
(
−1
/5
c+c)+(2)=2c−4 (Combine Like Terms)
4
/5
c+2=2c−4
4
/5
c+2=2c−4
Step 2: Subtract 2c from both sides.
4/5
c+2−2c=2c−4−2c
−6
/5
c+2=−4
Step 3: Subtract 2 from both sides.
−6
/5
c+2−2=−4−2
−6
/5
c=−6
Step 4: Multiply both sides by 5/(-6).
(
5
/−6
)*(
−6
/5
c)=(
5
/−6
)*(−6)
c=5
Answer:
c=5
Answer:
16
Step-by-step explanation:
Since line CE is equal to 32 and line DB is the bisector (cut into the middle) of line CE then line CF would be half of line CE. Hence the reason that line CF is equal to 16
Answer:
B C E
Step-by-step explanation:
Read the question
Answer:
Solutions are (6,3) and (-2,3).
Step-by-step explanation:
From the first equation given we can write:
substituting for
in the second equation given we get


∴ y=3
Putting y=3 in the first equation we get

x-2 = ±4
Hence x=6 or x=-2.