Range is the set of all values which the given function can output. The correct option is A.
<h3>What is domain and range of a function?</h3>
- Domain is the set of values for which the given function is defined.
- Range is the set of all values which the given function can output.
Since y is the output for the given function, and the only outputs that can be seen for the function are 0, 2, and 4. Therefore, the range of the function is {0,2,4}.
Hence, the correct option is A.
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Answer: 7 rows
Step-by-step explanation:
she will have 7 rows with 4 seats in each row or 4 rows with 7 seats in each row
Answer: The median score will remain the same at 91.
Step-by-step explanation: The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average. Write all of the numbers and cross out a even amount of numbers on both sides. Image 1 shows the problem with original numbers. Image 2 shows problem with new numbers
If you plot these points on a coordinate plane, you see that both vertices and foci lie on the y axis. This means that you have a vertical hyperbola, and the equation looks like this:
![\frac{(y-k) ^{2} }{ a^{2} } - \frac{(x-h) ^{2} }{ b^{2} } =1](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28y-k%29%20%5E%7B2%7D%20%7D%7B%20a%5E%7B2%7D%20%7D%20-%20%5Cfrac%7B%28x-h%29%20%5E%7B2%7D%20%7D%7B%20b%5E%7B2%7D%20%7D%20%3D1)
where h and k are the center. When you look at your graph, the origin is dead center between the vertices. (0, 0) is our h and k. Now we need a, b, and c. a is the distance between the center and the vertices, so our a = 4, and c is the distance between the center and the foci, so our c = 5. Use these in Pythagorean's Theorem to solve for b:
![(4) ^{2}+ b^{2}=(5) ^{2}](https://tex.z-dn.net/?f=%284%29%20%5E%7B2%7D%2B%20b%5E%7B2%7D%3D%285%29%20%5E%7B2%7D%20%20%20)
and
![16+ b^{2} =25](https://tex.z-dn.net/?f=16%2B%20b%5E%7B2%7D%20%3D25)
and b = 3. So we have all we need to do is replace all the variables. Our equation then would be this one:
![\frac{(y-0) ^{2} }{16} - \frac{(x-0) ^{2} }{9} =1](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28y-0%29%20%5E%7B2%7D%20%7D%7B16%7D%20-%20%5Cfrac%7B%28x-0%29%20%5E%7B2%7D%20%7D%7B9%7D%20%3D1)
or, simplified,