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Irina-Kira [14]
2 years ago
15

2x^2 + 19x + 40 = -2

Mathematics
2 answers:
hodyreva [135]2 years ago
4 0
Here’s the answer !Hope this helps!

liberstina [14]2 years ago
4 0

Answer:

X = - 7/2 or -6

Step-by-step explanation:

2x^2 + 19x + 40 = -2

2x^2 +19x + 40+2 = 0

2x^2 + 12x +7x+42= 0

2x(x+6) 7(x+6) =0

(2x+7) (x+6) = 0

2x+7 = 0

2x = -7

2x÷2=-7÷2

X= -7÷2 and

X+6=0

X=-6

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Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

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Answer:

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b) low range = 12

High range = 24

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Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

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