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mr_godi [17]
2 years ago
10

In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

length of SQ?

Mathematics
2 answers:
Sidana [21]2 years ago
6 0

Step 1    

<u>Find the value of TS</u>

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

\frac{TR}{TP} =\frac{TS}{QT}

solve for TS

TS =\frac{TR*QT}{TP}

we have

RP=2\ cm\\TP=18\ cm\\QT=27\ cm

TR=TP+RP\\TR=18+2=20\ cm

substitute

TS =\frac{20*27}{18}  

TS =30\ cm

Step 2

<u>Find the value of SQ</u>

we know that

SQ=TS-QT

we have

TS =30\ cm

QT=27\ cm

substitute

SQ=30\ cm-27\ cm=3\ cm

therefore

<u>the answer is</u>

the value of SQ is 3\ cm

Marizza181 [45]2 years ago
4 0

Answer: C. 3cm

Step-by-step explanation:

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ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

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at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

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Now let           F(t) = D^2(t)

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3 0
3 years ago
Find the perimeter use pi
balandron [24]
Since d x pi = circumference
I use 3.14 as pie

I did 9 x pi = 28.26 I DID NOT divide this by two because there are three half circles and 28.26 counts as two of them

Since there is another half circle I divide 28.26 by 2

28.26 + 14.13 = 42.39

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42.39 + 9 = 51.39


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7 0
3 years ago
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