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3 years ago

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In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

length of SQ?

2 answers:

Sidana [21]3 years ago

6 0

Step 1

<u>Find the value of TS</u>

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

$\frac{TR}{TP} =\frac{TS}{QT}$

solve for TS

$TS =\frac{TR*QT}{TP}$

we have

$RP=2\ cm\\TP=18\ cm\\QT=27\ cm$

$TR=TP+RP\\TR=18+2=20\ cm$

substitute

$TS =\frac{20*27}{18}$

$TS =30\ cm$

Step 2

<u>Find the value of SQ</u>

we know that

$SQ=TS-QT$

we have

$TS =30\ cm$

$QT=27\ cm$

substitute

$SQ=30\ cm-27\ cm=3\ cm$

therefore

<u>the answer is</u>

the value of SQ is $3\ cm$

Marizza181 [45]3 years ago

4 0

Answer: C. 3cm

Step-by-step explanation:

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