Answer:
53
Step-by-step explanation:
the outer measurements are the correct one
Given:
3kg book
speed of falling of 4.0 m/s
acceleration due to gravity -9.8 m/s²
Vf² = Vi² + 2 * a * d
Vf = final velocity ; Vi = initial velocity ; a = acceleration ; d = distance
0² = (4 m/s)² + 2(-9.8m/s²) * d
0 = 16 m²/s² -19.6 m/s² * d
-16 m²/s² = -19.6 m/s² * d
-16 m²/s² / -19.6 m/s² = d
0.82 m = distance
The 3 kg book fell from the a shelf at the height of 0.82 meters.
Answer:
1/2 and 3
Step-by-step explanation:
The quadratic formula is as given:
( -b±√(b^2-4ac) )/2a
To use it, plug in the a,b and c values.
ax^2+bx+c
In this case a is equal to 2, b is equal to -7, and c is equal to 3
plugging it into our formula gives us:
(-(-7)±√(-7^2-4*2*3) )/2*2
Which is equal to:
7±√(49-24) / 4
= 7±√25 / 4
=7±5 / 4
=2/4, 12/4= 1/2, 3