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1 year ago

-3x+4-1=4x determine if an expression or equation

Mathematics

1 answer:

Natali [406]1 year ago

6 0

- 3x + 4 - 1 = 4x is an equation.

<h3>What is an equation?</h3>

The equal symbol (=) connects the two sides of the equation expression. 2x+1 is the left-hand side (LHS) of the equation, and 9 is the expression's right-hand side (RHS). The LHS value is equal to the RHS of the expression, as shown by the equal sign between LHS and RHS.

It is not an equation when 10x + 63 > 10. The expression's sign between the LHS and RHS in this case is not equal. We can therefore claim that not every expression is an equation. Linear inequalities are a class of expressions that fit this description.

- 3x + (4 -1) = 4x

- 3x - 4x = - 3

3x + 4x = 3

7x = 3

3/7 = x

To know more about expressions and equations, visit:

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The graph of y= f(X) is shown below, what point could be used to find f(3)?

balandron [24]

Answer:

Point A

Step-by-step explanation:

The long that would be used to find f(3) is the point that shows the value of y when x = 3.

Looking at the graph given, the only point that shows the value of y when x = 3 is point A.

When x = 3, y = 0.

Therefore, f(3) = 0.

8 0

3 years ago

Please help and work out both questions! ill give brainlest and 20 points

raketka [301]

Answer:

Step-by-step explanation:

6. Use PEMDAS

-3 x (7 + (-3)*2) / 3

-3 x (7 + 9) / 3

-3 x 16 / 3

-48 / 3

-16

7. 9 (x) = -63

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6 0

3 years ago

Read 2 more answers

Given that:3x+2=2 and 5-6=y

sergeinik [125]

3x+2=2
3x=0
x=0
5-6=y
y=-1

8 0

3 years ago

Find the absolute value:<br> 5.34 -4 2/11 0<br> -6 3/5 -2.12 8.2

earnstyle [38]

Answer:

Change the positive numbers to negative and change the negative numbers to positive.

Step-by-step explanation:

I hope this helps u! :D

6 0

3 years ago

Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

3 years ago